A 2.40 kg hoop (1 = MR^2) of radius 0.200 m rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear speed of 3.90 m/s. What is the total kinetic energy of the hoop? Q V

icon
Related questions
Question
A 2.40 kg hoop (1 = MR^2) of radius 0.200 m rolls without slipping on a horizontal
surface so that its center proceeds to the right with a constant linear speed of 3.90
m/s. What is the total kinetic energy of the hoop?
Transcribed Image Text:A 2.40 kg hoop (1 = MR^2) of radius 0.200 m rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear speed of 3.90 m/s. What is the total kinetic energy of the hoop?
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer