A 2.40 kg hoop (1 = MR^2) of radius 0.200 m rolls without slipping on a horizontal surface so that its center proceeds to the right with a constant linear speed of 3.90 m/s. What is the total kinetic energy of the hoop? Q V
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- A 0.22kg solid cylinder is released from rest at the top of a ramp and travels 1.5m to the bottom. The cylinder has a radius of 0.15m, and the ramp is at an angle of 15 degree with the horizontal. What is the rotational kinetic energy of the cylinder when it reaches the bottom of the ramp?A disk of mass M and radius R sits on top of an incline of height h. From rest, it then rolls without slipping down the incline. h R The equation for conservation of energy as the disk falls down the incline is shown below: Initially, the disk only has potential energy given by Ma(h+ R). At the ground, the disk has a potential energy of MgR, and kinetic energy from rotational and translational motion. We then have Mg(h + R) = MgR+ /1w² + = M(Rw)², where I = MR². Calculate the angular speed of the disk as it rolls down the bottom of the incline. (Provide full solution of the problem).The rigid body shown in the figure consists of three particles connected by massless rods. It is to be rotated about an axis perpendicular to its plane through point P. If M = 0.41 kg, a = 35 cm, and b = 53 cm, how much work is required to take the body from rest to an angular speed of 5.8 rad/s? M 2M Number Units J
- A car tire (hoop) has a mass of 35 kg and a radius of 0.43 m. The tire is released from rest at the top of a hill and it rolls without slipping to the bottom. “Rolls without slipping” means that the linear velocity of the center of mass is equal to the tangential velocity at the edge of the tire. Once the tire reaches the bottom of the hill it will have dropped by 10 m in vertical height. The final angular velocity ?ω of the tire at the bottom of the hill is Answer ????rads.A cylinder of radius 2.59 cm and a sphere of radius 8.72 cm are rolling without slipping along the same floor. The two objects have the same mass. If they are to have the same total kinetic energy, what should the ratio of the cylinder's angular speed ?cyl to the sphere's angular speed ?sph be?R M A solid sphere of uniform density starts from rest and rolls without slipping down an inclined plane with angle 0 = 30°. The sphere has mass M = 8 kg and radius R = 0.19 m . The coefficient of static friction between the sphere and the plane is u = 0.64. What is the magnitude of the frictional force on the sphere? Ff =
- Problem 7 : A sphere of radius r0 = 24.0 cm and mass m = 1.20kg starts from rest and rolls without slipping down a 33.0∘ incline that is 15.0 m long. Part A Calculate its translational speed and rotational speed when it reaches the bottom. Does the answers depend on mass or radius of the ball? Part C What is the ratio of translational to rotational kinetic energy at the bottom?(Ktr/Krot=?) Does the answer depend on mass or radius of the ball?Your grandmother enjoys creating pottery as a hobby. She uses a potter's wheel, which is a stone disk of radius R = 0.540 m and mass M = 100 kg. In operation, the wheel rotates at 45.0 rev/min. While the wheel is spinning, your grandmother works clay at the center of the wheel with her hands into a pot-shaped object with circular symmetry. When the correct shape is reached, she wants to stop the wheel in as short a time interval as possible, so that the shape of the pot is not further distorted by the rotation. She pushes continuously with a wet rag as hard as she can radially inward on the edge of the wheel and the wheel stops in 6.00 s. You would like to build a brake to stop the wheel in a shorter time interval, but you must determine the coefficient of friction (?k) between the rag and the wheel in order to design a better system. You determine that the maximum pressing force your grandmother can sustain for 6.00 s is 65.0 N. What If? If your grandmother instead chooses to press…A m = 2kg ring has a radius of r = 0.5m. The moment of inertia of a ring is I = m r². The ring has an initial speed of v= 1 m/s on the horizontal surface. It rolls, without slipping, along the surface and up the ramp, where it stops when it reaches a height h. a) What is the angular velocity of the ring when it is on the horizontal surface? v=1m/s b) While the ring is on the horizontal surface, what is the speed of a point at the top of the ring? c) Use Conservation of Energy to find the maximum height of the ring, h. Show all your work. Solve the problem using variables. Only substitute numbers in the very last step. d) How would the maximum height change in each of the following situations? Put an X in the correct answer for each statement. The ring has a larger mass m (same r and v) The ring is replaced with a solid disc (same m, r, and v) There is no friction and the ring slides instead of rolling (same m, r, and v) Higher v=0 Lower Same height h
- A uniform sphere is placed inside hemispherical bowl of radius R = 75.0 cm. It is released from rest at an angle 0 = 40.0°. What is the speed of the sphere at the bottom of the bowl if it rolls without slipping? Ishpere = 2/5 mr². Assume r<A hollow ball of mass m = 2.0 kg and radius r rolls without slipping along a loop-the-loop track, with a height of h and radius R. The ball is released from rest somewhere on the straight section of the track. a. From what minimum height h above the bottom of the track must the ball be released in order that it not leave the track at the top of the loop? (height of loop is 2R) The Radius is 10.0 m b. What is acting as a radial force at the top of the loop? (gravity, Tension ???) I hollow ball = (2/3) mr² gninub 21 noitu boxil bns brossz sri gnitub suprot sit zomit auol (C doum asmuomo (3 2R di grois un 12 What was the potential energy at the top of mass m? HoumA solid 0.6350 kg ball rolls without slipping down a track toward a vertical loop of radius ?=0.6350 m. What minimum translational speed ?min must the ball have when it is a height ?=0.9944 m above the bottom of the loop in order to complete the loop without falling off the track? Assume that the radius of the ball itself is much smaller than the loop radius ?. Use ?=9.810 m/s^2 for the acceleration due to gravity.SEE MORE QUESTIONS