A 2.25 m length of wire is held in an east–west direction and moves horizontally to the north with a speed of 14.7 m/s. The vertical component of Earth's magnetic field in this region is 40.0 uT directed downward. Calculate the induced emf between the ends of the wire and determine which end is positive.

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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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A 2.25 m length of wire is held in an east–west direction and moves horizontally to the north with a speed of 14.7 m/s. The vertical component of Earth's magnetic field in this region is 40.0 uT directed downward. Calculate the induced emf between the ends of the wire and determine which end is positive.

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In the following problem, 

We have a wire of length l held in in east-west direction and moves horizontally to north with the speed v.

Length of the wire, l=2.25 m

Speed of the wire, v=14.7  m/s (north)

Vertical component of Earth's magnetic field, B=40 μT (downward)

 

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