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A 2.0 L solution made by adding solid NaCIO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaCIO were originally added? Ka of HCIO is 3.0 x 10 7. 3. NEXT Let x represent the original concentration of CIO in the water. Based on the given values, set up the ICE table in order to determine the unknown. CIO (aq) H2O(I) Он (аq) HCIO(aq) Initial (M) Change (M) -3.2 x 104 3.2 x 104 3.2 x 104 Equilibrium (M) x- 3.2 x 104 3.2 x 104 3.2 x 104 RESET 2.0 10.50 3.0 x 10-7 2x 0.5x -2x -0.5x 3.2 x 10-11 -3.2 x 10-11 3.2 x 104 -3.2 x 104 x + 3.2 x 10-11 -x x - 3.2 x 10-11 x+ 3.2 x 104 x - 3.2 x 104

A 2.0 L solution made by adding solid NaCIO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaCIO were originally added? Ka of HCIO is 3.0 x 10 7. 3. NEXT Let x represent the original concentration of CIO in the water. Based on the given values, set up the ICE table in order to determine the unknown. CIO (aq) H2O(I) Он (аq) HCIO(aq) Initial (M) Change (M) -3.2 x 104 3.2 x 104 3.2 x 104 Equilibrium (M) x- 3.2 x 104 3.2 x 104 3.2 x 104 RESET 2.0 10.50 3.0 x 10-7 2x 0.5x -2x -0.5x 3.2 x 10-11 -3.2 x 10-11 3.2 x 104 -3.2 x 104 x + 3.2 x 10-11 -x x - 3.2 x 10-11 x+ 3.2 x 104 x - 3.2 x 104

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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what should i put for the numinator of the Kb equation. Because the value of Kw is not in the options for me tu put in the numinator ? 

Question 13 of 13 A 2.0 L solution made by adding solid NaCIO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaCIO were originally added? Ka of HCIO is 3.0 x 10 7. 1 3. NEXT へ Let x represent the original concentration of CIO in the water. Based on the given values, set up the ICE table in order to determine the unknown. CIO (aq) H2O(1) OH (aq) HCIO(aq) + Initial (M) Change (M) -3.2 x 10-4 3.2 x 104 3.2 x 10-4 Equilibrium (M) x - 3.2 x 104 3.2 x 10 4 3.2 x 10-4 5 RESET 2.0 10.50 3.0 x 10-7 2x 0.5x -2x -0.5x 3.2 x 10-11 -3.2 x 10-11 3.2 x 104 -3.2 x 104 x + 3.2 × 10-11 x - 3.2 × 10-11 x + 3.2 x 10-4 X - 3.2 x 10-4 1L
Transcribed Image Text:Question 13 of 13 A 2.0 L solution made by adding solid NaCIO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaCIO were originally added? Ka of HCIO is 3.0 x 10 7. 1 3. NEXT へ Let x represent the original concentration of CIO in the water. Based on the given values, set up the ICE table in order to determine the unknown. CIO (aq) H2O(1) OH (aq) HCIO(aq) + Initial (M) Change (M) -3.2 x 10-4 3.2 x 104 3.2 x 10-4 Equilibrium (M) x - 3.2 x 104 3.2 x 10 4 3.2 x 10-4 5 RESET 2.0 10.50 3.0 x 10-7 2x 0.5x -2x -0.5x 3.2 x 10-11 -3.2 x 10-11 3.2 x 104 -3.2 x 104 x + 3.2 × 10-11 x - 3.2 × 10-11 x + 3.2 x 10-4 X - 3.2 x 10-4 1L
Question 13 of 13 A 2.0 L solution made by adding solid NaCIO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaCIO were originally added? Ka of HCIO is 3.0 x 10 7. PREV 1 3. NEXT > Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do not combine or simplify terms. Kb %3D 5 RESET [0] [2.0] [10.50] [3.50] [x] [2x] [0.5x] [3.2 x 10-1"] [x + 3.2 x 10-11] [x - 3.2 x 10-11] [x + 3.2 x 10] [x - 3.2 x 104] 3.0 x 10-7 3.3 x 106 [3.2 × 10-] 3.3 x 10-8 3.0 x 107
Transcribed Image Text:Question 13 of 13 A 2.0 L solution made by adding solid NaCIO to water resulted in a basic equilibrium with a pH of 10.50. How many moles of NaCIO were originally added? Ka of HCIO is 3.0 x 10 7. PREV 1 3. NEXT > Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine the unknown. Do not combine or simplify terms. Kb %3D 5 RESET [0] [2.0] [10.50] [3.50] [x] [2x] [0.5x] [3.2 x 10-1"] [x + 3.2 x 10-11] [x - 3.2 x 10-11] [x + 3.2 x 10] [x - 3.2 x 104] 3.0 x 10-7 3.3 x 106 [3.2 × 10-] 3.3 x 10-8 3.0 x 107
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