A 191.0 pF capacitor is charged to a potential difference of 71 V, and the charging battery is disconnected. The capacitor is then connected in parallel with a second (initially uncharged) capacitor. If the measured potential difference across the first capacitor drops to 31 V, what is the capacitance (in pF) of this second capacitor?
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- The plates of a parallel plate capacitor each have an area of 1.0m^2 and are separated by a distance of 0.01 m. What is the capacitance of this capacitor?Three capacitors are connected in series to a CR123 lithium battery where one has dielectrics between its plates (C345). Capacitor C345 has a plate area of A=200cm2, a plate separation distance of d=0.2μm and has three dielectrics with constants K3=3, K4=4.2, and K5=5.3. What is the capacitance of the C345 capacitor in μF?Four uncharged capacitors with equal capacitances are combined in series. The combination is connected to a 7.65 V battery, which charges the capacitors. The charging process involves 0.000193 C of charge moving through the battery. Find the capacitance C of each capacitor. C = F
- A 5.0 μ F capacitor is connected to a 12-volt ideal battery. While the battery is connected, a dielectric (κ = 2) is inserted into the capacitor. What is the charge on the capacitor?Consider a cylindrical capacitor with inner radius r1 = 8.1 cm, outer radius r2 = 14.3 cm, and length L = 16.7 cm. A dielectric with dielectric constant κ = 53 fills the volume between the two cylinders. The capacitor is connected to a 106.6 V battery and is fully charged. What is the charge on the capacitor? Express your answer in Coulombs to 3 significant figures.Problem 6: Suppose you have a 9.00 V battery, a 3.8 μF capacitor, and a 7.85 μF capacitor. Part (a) Find the total charge stored in the system if the capacitors are connected to the battery in series in C. Part (b) Find the energy stored in the system if the capacitors are connected to the battery in series in J. Part (c) Find the charge if the capacitors are connected to the battery in parallel in C. Part (d) Find the energy stored if the capacitors are connected to the battery in parallel in J.
- A parrallel plate capacitor consisting of two 30.0 cm x 30.0 cm square conductors are separated by a 3.00 mm piece of mica (k=5.00) is charged by a connecting it to an 18.0 V battery. What is the capacitance of this capacitor? What is the charge on the capacitor? If the mica is removed and replaced with glass (k=7.00), what is the potential difference of the plates now? What is the charge on the capacitor now with the glass?A capacitor has a voltage difference between its terminals of 1.3 V. The amount of charge stored in the capacitor is 16 uC. What is the capacitance of the capacitor?A parallel plate capacitor has an equivalent capacitance of 850 pF. The area of each plate is 6 cm^2 and the thickness of the dielectric is 0.02 cm. If the material used as the dielectric has a constant of 8, how many sections are there in parallel?
- Two plates, each of area 5.30 cm², are 2.59 mm apart in a parallel plate capacitor. The space between the plates is filled with two different dielectric materials. The left half of the capacitor is filled with a material whose dielectric constant K, = 5.50. The right half of the capacitor is filled with a material of unknown dielectric value K2. The capacitance of this device is 7.95 pF. Find the value of K2. Additional Materials еBook e Show My Work (Optional) ?An engineer connects a 24.0 V battery to a capacitor of unknown capacitance. The result is that 52.0 µC of charge is stored on the capacitor. How much energy (in J) is stored in the capacitor?The capacitance of an empty capacitor is 1.2 μF. The capacitor is connected to a 12-V battery and charged up. With the capacitor connected to the battery, a slab of dielectric material is inserted between the plates. As a result, 2.6 × 10–5 C of additional charge flows from one plate, through the battery, and onto the other plate. What is the dielectric constant of the material?