A 180kW, 230V, 435 rpm dc shunt motor has a nominal full-load current of 860A.(a) Calculate the total losses and efficiency at full load and rated speed.(b) Find the shunt field exciting current if the shunt field causes 20% of the total losses.(c) Calculate the value of the armature resistance and the back emf, if 50% of the totallosses at full-load are attributable to the armature resistance. [(d) Find the field current to make the motor run at 1000 rpm under no load. [C(e) Identify the motor efficiency if it is operating at half rated current at 1000 rpm. Assumethat mechanical losses are linearly proportional to speed. [C

As per the guidelines, we supposed to answer first three part of the question at a time so please…

Answered: A 180kW, 230V, 435 rpm dc shunt motor…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

A 200 V dc shunt motor takes a current of 20A on a certain load. R= 12 and Rah= 2002. Find the resistance to be inserted in series with the armature to reduce the speed to 75% of its original value if the load torque is constant.
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A 10 kW, 250V shunt motor has an armature resistance of 0.5ohm and a field resistance of 200ohm. At no load and rated voltage, the speed is 1200 rpm and the armature current is 3A. At full load and rated voltage, the current line is 47A and because of armature reaction, the flux is 4% less than it no load value. (a.) What is the full load speed? (b.)What is the developed torque at full load? 1158 rpm
1. The rotor resistance and reactance per phase of a three-phase wound rotor induction motor are 0.035 and 0.15 ohm respectively. If an additional resistance is added, the starting torque is one half of maximum torque and the full load torque is three-fourth of the maximum. Determine the following: a. Full load speed b. speed at maximum torque c. value of additional resistance per required to achieve these conditions.
On full-load a 300 V series motor takes 90A and runs at 15 rev/s. The armature resistance is 0.1 ohm and the series winding resistance is 50 m.Determine the speed when developing full load torque but with a 0.2 ohm diverter in parallel with the field winding. (Assume that the flux is proportional to the field current.
7-5. A 50-kW, 440-V, 50-Hz, six-pole induction motor has a slip of 6 percent when op- erating at full-load conditions. At full-load conditions, the friction and windage losses are 300 W, and the core losses are 600 W. Find the following values for full- load conditions: (a) The shaft speed n. (b) The output power in watts (c) The load torque Tloud in newton-meters (d) The induced torque Tiad in newton-meters (e) The rotor frequency in hertz
A 3-phase, 220-V, 50-Hz, 6-pole, Y-connected induction motor is operating with a per-unit slip of 0.07, 95 A line current, PF=0.8 lagging, and 2200 W stator copper losses. The total friction, windage, and core losses are lumped and assumed to be constant at 3.5 KW. Find the rotor copper losses and the output power of this motor? Select one: O a. None O b. PRCI = 1.08 KW and Pout = 18.8 KW O c. PRCL = 1.87 KW and Pout = 21.4 KW O d. PRCL = 10.5 KW and Pout = 29.14 KW
Q1: Fill in the following blanks: 1. In order to have sparkless commutation, the brushes should be placed along... 2. D.C. series motor are used in those applications where... required. 3. The self-induction of a coil undergoing commutation causes .. . at the brushes. .starting torque is
A wound-field DC motor has an armature resistance of 0.50 0 and a mechanical loss torque of 1.0 Nm at full-load speed. The armature voltage is 240 V and the no-load speed of the motor is 2500 rpm. If at full-load the shaft torque is 60.0 Nm and the field flux is reduced by 5% at full-load, determine: (i) The value of Kø,, where K is the armature constant and of is the field flux, at no-load and full-load. (ii) The full-load armature current. (iii) The full-load motor speed. (iv) The full-load efficiency of the motor if the power lost in the field winding is 100 W.

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