A 180-g billiard ball is shot toward an identical ball at velocity vi = 6.90 m/s. The identical ball is initially at rest. After the balls hit, one of them travels with velocity v1, f = (1.80 + 2.22) m/s. What is the velocity of the second ball after the impact? Ignore effects of friction during this process. (Express your answer in vector form.) v2, f = m/s

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Chapter1: Units, Trigonometry. And Vectors
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A 180-g billiard ball is shot toward an identical ball at velocity 

vi = 6.90 m/s.

 The identical ball is initially at rest. After the balls hit, one of them travels with velocity 

v1, f = (1.80 + 2.22) m/s.

 What is the velocity of the second ball after the impact? Ignore effects of friction during this process. (Express your answer in vector form.)

v2, f = 
 
 
 
 m/s
Expert Solution
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mass of each billiard's ball (m) = 180 g initial velocity of first ball = 6.90 m/s initial velocity of second ball = 0 m/s final velocity of one of the balls (v1f) = (1.80i^ +2.22j^) m/s 

 

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