A 18.0 mL sample of vinegar, which is an aqueous solution of acetic acid, CH3COOH, requires 15.5 mL of a 0.350 M solution of NaOH to reach the endpoint in a titration: Part A CH3COOH(aq) + NaOH(aq) → NaCH3CO0(aq) + H2O(1) What is the molarity of the acetic acid solution? You may want to reference (Pages 346 - 350) Section 10.7 while completing this problem. Express the concentration to three significant figures and include the appropriate units. HẢ Value Units Submit Request Answer Provide Feedback

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<Chapters 5, 8, 9 ,10 in a nutshell
Problem 10.96 - Enhanced - with Feedback
47 of 50
I Review | Constants | Periodic Table
A 18.0 mL sample of vinegar, which is an aqueous solution of acetic
acid, CH3COOH, requires 15.5 mL of a 0.350 M solution of
NaOH to reach the endpoint in a titration:
Part A
CH3COOH(aq) + NaOH(aq) → NACH3COO(aq) + H2O(1)
What is the molarity of the acetic acid solution?
You may want to reference (Pages 346 - 350) Section 10.7 while
completing this problem.
Express the concentration to three significant figures and include the appropriate units.
HẢ
?
Value
Units
Submit
Request Answer
Provide Feedback
Next >
Transcribed Image Text:<Chapters 5, 8, 9 ,10 in a nutshell Problem 10.96 - Enhanced - with Feedback 47 of 50 I Review | Constants | Periodic Table A 18.0 mL sample of vinegar, which is an aqueous solution of acetic acid, CH3COOH, requires 15.5 mL of a 0.350 M solution of NaOH to reach the endpoint in a titration: Part A CH3COOH(aq) + NaOH(aq) → NACH3COO(aq) + H2O(1) What is the molarity of the acetic acid solution? You may want to reference (Pages 346 - 350) Section 10.7 while completing this problem. Express the concentration to three significant figures and include the appropriate units. HẢ ? Value Units Submit Request Answer Provide Feedback Next >
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