Answered: A 17-Ω television and an 45-Ω amplifier…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A 17-Ω television and an 45-Ω amplifier are connected in series across a 133-V source of voltage from an outlet. A 34-Ω light bulb is also connected across the 133-V source and is in parallel with the series combination.

(a) Determine the total rms current supplied by the voltage source. in amps
(b) Determine the total average power supplied by the voltage source. in watts

Expert Solution

Step 1

The total series combination of the resistors is,

$\begin{array}{rcl} R_{s} & = & 17 Ω + 45 Ω \\ = & 62 Ω \end{array}$

The total resistance is,

$\begin{array}{rcl} \frac{1}{R} & = & \frac{1}{62} + \frac{1}{34} \\ \frac{1}{R} & = & 0.046 \\ R & = & \frac{1}{0.046} \\ = & 21.7 Ω \end{array}$

(a)

The total current supplied by the voltage source is,

$\begin{array}{rcl} I_{0} & = & \frac{V}{R} \\ = & \frac{133 V}{21.7 Ω} \\ = & 6.13 A \end{array}$

The total rms current is,

$\begin{array}{rcl} I_{r m s} & = & \frac{I_{0}}{\sqrt{2}} \\ = & \frac{6.13 A}{1.414} \\ = & 4.34 A \end{array}$

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