A 1,500 kVA, 2300 V, 60 Hz, 3 phase, wye-connected generator has a synchronous impedance of 0.06 + j1 ohms/phase. Field current is 60 A at 125 V dc. Find the percent efficiency of the alternator at full load, 2300 V and 0.9 pf lagging at the above condition. The core and friction losses are 25 kW and 18 kW, respectively. a. 96.8% c. 94.67% b. 93.28% d. 95.15%
A 1,500 kVA, 2300 V, 60 Hz, 3 phase, wye-connected generator has a synchronous impedance of 0.06 + j1 ohms/phase. Field current is 60 A at 125 V dc. Find the percent efficiency of the alternator at full load, 2300 V and 0.9 pf lagging at the above condition. The core and friction losses are 25 kW and 18 kW, respectively. a. 96.8% c. 94.67% b. 93.28% d. 95.15%
Introductory Circuit Analysis (13th Edition)
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. A 1,500 kVA, 2300 V, 60 Hz, 3 phase, wye-connected generator has a synchronous impedance of 0.06 +
j1 ohms/phase. Field current is 60 A at 125 V dc. Find the percent efficiency of the alternator at full load,
2300 V and 0.9 pf lagging at the above condition. The core and friction losses are 25 kW and 18 kW,
respectively
![A 1,500 kVA, 2300 V, 60 Hz, 3 phase, wye-connected generator has a synchronous impedance of 0.06 +
j1 ohms/phase. Field current is 60 A at 125 V dc. Find the percent efficiency of the alternator at full load,
2300 V and 0.9 pf lagging at the above condition. The core and friction losses are 25 kW and 18 kW,
respectively.
a. 96.8%
c. 94.67%
b. 93.28%
d. 95.15%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F659e070a-15ca-4f9c-9e6b-63edfccb1832%2F74ecb59e-f095-448e-8ba4-b0674a19b93c%2Fnec8wq_processed.png&w=3840&q=75)
Transcribed Image Text:A 1,500 kVA, 2300 V, 60 Hz, 3 phase, wye-connected generator has a synchronous impedance of 0.06 +
j1 ohms/phase. Field current is 60 A at 125 V dc. Find the percent efficiency of the alternator at full load,
2300 V and 0.9 pf lagging at the above condition. The core and friction losses are 25 kW and 18 kW,
respectively.
a. 96.8%
c. 94.67%
b. 93.28%
d. 95.15%
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