A 150.9-g sample of a metal at 74.5°C is added to 150.9 g H2O at 15.1°C. The temperature of the water rises to 18.4°C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water. The specific heat capacity of water is 4.18 J/°C•g. Specific heat capacity = J/°C•g

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A 150.9-g sample of a metal at 74.5°C is added to 150.9 g H₂O at 15.1°C. The temperature of the water rises to 18.4°C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water. The specific heat capacity of water is 4.18 J/°C·g.

Specific heat capacity = [_____] J/°C·g

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Transcribed Image Text:A 150.9-g sample of a metal at 74.5°C is added to 150.9 g H₂O at 15.1°C. The temperature of the water rises to 18.4°C. Calculate the specific heat capacity of the metal, assuming that all the heat lost by the metal is gained by the water. The specific heat capacity of water is 4.18 J/°C·g. Specific heat capacity = [_____] J/°C·g Buttons: - Submit Answer - Try Another Version Note: 3 item attempts remaining. Orange button labeled "Not Visited".
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The specific heat capacity of is defined as a substance is having energy which is required to raise the temperature of 1 Kg of a substance by 1 degree Celsius.

q = mcTq = heat m = mass of a susbtanceT = temeprature difference

Given values:

mass of metal = 150.9 g

mass of water = 150.9 g

T for metal,Tf =18.4C°Ti = 74.5 C°T for water,Tf =18.4C°Ti =15.1 C°

c = 4.18 J/gC°

 

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