A 14.0 kg rock slides down a hill, leaving point A with a speed of 12 m/s. There is no friction between point A and B. There is friction on the level surface between point B and the wall (where the spring is located). a) What is the speed of the rock when it reaches point B (bottom of the hill). b) After reaching B, the rock travels 100m on the level surface until it hits a very long light spring (k = 2.00 N/m). How far will the rock compress (maximum compression) the spring? VA 12 m/s No friction. This equation may be useful ax²+bx+c=0-x-- Rough surface with friction -b± √b²-4ac 2a Spring at

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Chapter1: Units, Trigonometry. And Vectors
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A 14.0 kg rock slides down a hill, leaving point A with a speed of 12 m/s.
There is no friction between point A and B. There is friction on the level surface
between
point B and the wall (where the spring is located).
a) What is the speed of the rock when it reaches point B (bottom of the hill).
b) After reaching B, the rock travels 100m on the level surface until it hits a very long
light spring (k= 2.00 N/m). How far will the rock compress (maximum compression)
the spring?
25 m
VA= 12 m/s
15 m
No friction
B
This equation may be useful
ax² +bx+c=0-x--
Rough surface with friction
Hk-0.2 and μ,-0.7
VB = ?
100 m
-b± √b²-4ac
2a
Spring at
equilibrium:
k = 2.00 N/m
W
Transcribed Image Text:A 14.0 kg rock slides down a hill, leaving point A with a speed of 12 m/s. There is no friction between point A and B. There is friction on the level surface between point B and the wall (where the spring is located). a) What is the speed of the rock when it reaches point B (bottom of the hill). b) After reaching B, the rock travels 100m on the level surface until it hits a very long light spring (k= 2.00 N/m). How far will the rock compress (maximum compression) the spring? 25 m VA= 12 m/s 15 m No friction B This equation may be useful ax² +bx+c=0-x-- Rough surface with friction Hk-0.2 and μ,-0.7 VB = ? 100 m -b± √b²-4ac 2a Spring at equilibrium: k = 2.00 N/m W
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