A 125 mg dust particle with a charge of -5 µC is suspended above a charged plate as shown below.Ball on a string6.5 cm172.5cmDetermine the magnitude of the E-field at the dust particle's location.E =Determine the direction of the E-field at the dust particle's locationDirection of E-field = ↓EDetermine the polarity of the plate.Polarity of the plate= positiveA 0.36 kg ball, with a charge of 7.5 mC hangs by a 6.5 cm long thread between two oppositely charged parallel plates as shown below. The plates create a uniform horizontal E-field.As a result, the ball has moved 2.5 cm from the vertical. (NOTE: Calling the E-field "uniform" means it's the exact same everywhere between the plates.)Determine the magnitude of the E-field.XDetermine the tension in the thread.FT =Determine the polarity of each plate. You will not receive credit until you have correctlyselected the polarities of both plates.left plateright platetions, determinthe electric forcpositive.tions, determinethe electric forcepositive.s, magnitude, &rce on E becausetions for this partrelative to the VER

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A 125 mg dust particle with a charge of -5 μC is suspended above a charged plate as shown below. Ball on a string 6.5 cm Determine the magnitude of the E-field at the dust particle's location. E = 2.5cm Determine the direction of the E-field at the dust particle's location Direction of E-field = ! ✓ ✔ A 0.36 kg ball with a charge of 7.5 mC hangs by a 6.5 cm long thread between two oppositely charged parallel plates as shown below. The plates create As a result, the ball has moved 2.5 cm from the vertical. (NOTE: Calling the E-field "uniform" means it's the exact same everywhere between the plates.) Determine the polarity of the plate. Polarity of the plate = positive Determine the magnitude of the E-field. E = Determine the tension in the thread. FT = uniform horizontal E-field. Determine the polarity of each plate. You will not receive credit until you have correctly selected the polarities of both plates. left plate right plate

A 125 mg dust particle with a charge of -5 μC is suspended above a charged plate as shown below. Ball on a string 6.5 cm Determine the magnitude of the E-field at the dust particle's location. E = 2.5cm Determine the direction of the E-field at the dust particle's location Direction of E-field = ! ✓ ✔ A 0.36 kg ball with a charge of 7.5 mC hangs by a 6.5 cm long thread between two oppositely charged parallel plates as shown below. The plates create As a result, the ball has moved 2.5 cm from the vertical. (NOTE: Calling the E-field "uniform" means it's the exact same everywhere between the plates.) Determine the polarity of the plate. Polarity of the plate = positive Determine the magnitude of the E-field. E = Determine the tension in the thread. FT = uniform horizontal E-field. Determine the polarity of each plate. You will not receive credit until you have correctly selected the polarities of both plates. left plate right plate

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A 125 mg dust particle with a charge of -5 µC is suspended above a charged plate as shown below.
Ball on a string
6.5 cm
17
2.5cm
Determine the magnitude of the E-field at the dust particle's location.
E =
Determine the direction of the E-field at the dust particle's location
Direction of E-field = ↓
E
Determine the polarity of the plate.
Polarity of the plate= positive
A 0.36 kg ball, with a charge of 7.5 mC hangs by a 6.5 cm long thread between two oppositely charged parallel plates as shown below. The plates create a uniform horizontal E-field.
As a result, the ball has moved 2.5 cm from the vertical. (NOTE: Calling the E-field "uniform" means it's the exact same everywhere between the plates.)
Determine the magnitude of the E-field.
X
Determine the tension in the thread.
FT =
Determine the polarity of each plate. You will not receive credit until you have correctly
selected the polarities of both plates.
left plate
right plate
tions, determin
the electric forc
positive.
tions, determine
the electric force
positive.
s, magnitude, &
rce on E because
tions for this part
relative to the VER

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