help what is the answer? ### Example Problem: Calculating the Magnetic Field Strength Inside a Solenoid#### Problem StatementA 12.9 cm long solenoid contains 817 turns and carries a current of 4.69 A. What is the strength \( B \) of the magnetic field at the center of this solenoid?#### SolutionTo calculate the magnetic field inside a solenoid, use the formula:\[ B = \mu_0 \cdot n \cdot I \]where:- \( B \) is the magnetic field,- \( \mu_0 \) is the permeability of free space \((4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A})\),- \( n \) is the number of turns per unit length (in turns per meter),- \( I \) is the current in amperes.First, convert the length of the solenoid from centimeters to meters:\[ \text{Length} = 12.9 \, \text{cm} = 0.129 \, \text{m} \]Calculate \( n \) (number of turns per unit length):\[ n = \frac{\text{Number of Turns}}{\text{Length}} = \frac{817}{0.129} \approx 6333.33 \, \text{turns/m} \]Now, plug in the values into the formula:\[ B = (4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A}) \cdot (6333.33 \, \text{turns/m}) \cdot (4.69 \, \text{A}) \]Calculate the product:\[ B \approx 0.00374 \, \text{T} \]So, the strength \( B \) of the magnetic field at the center of the solenoid is approximately 0.00374 T.##### Final Answer\[ B \approx 0.00374 \, \text{T} \]

Length of solenoid (L) = 12.9 cm = 0.129 m Number of turns (N) = 817 Current (I) = 4.69 A

Answered: A 12.9 cm long solenoid contains 817…

A 12.9 cm long solenoid contains 817 turns and carries a current of 4.69 A. What is the strength B of the magnetic field at the center of this solenoid? B = T

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter29: Sources Of The Magnetic Field

Section: Chapter Questions

Problem 37AP: A very large parallel-plate capacitor has uniform charge per unit area + on the upper plate and on...

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