A 12.48g sample of an unknown metal, heated to 99.0˚C was then plunged into 50.0mL of 25.0˚C water. The temperature of the water rose to 28.1˚C. Assuming no loss of energy to the surroundings. How many joules of energy did the water absorb

Q: If 1101 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g•°C)…

A: HEAT ENERGY: When the atoms present in a compound which can be a solid, liquid or a gaseous molecule…

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A: Calorimetry is used to measure the transfer of heat taking place in a system. In this process, the…

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A: Given, mass (m) = 809.0 mg = 0.809 g Initial temperature (Ti) = 52.2 °C = (52.2 + 273.15) K = 325.35…

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A: Given that, for a 576.0 mg of pure substance, 10.1 J of heat is required to raise the temperature…

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A: Given: mass of substance = 1.91 kg = 1910 g Temperature change = 0.6°C to 15.5°C Heat needed = 3.96…

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A: Use the concept of heat lost by metal = heat gained by water to calculate specific heat of the…

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A: Answer

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Q: A piece of metal was placed into a 75.00 grams of water. The temperature of the water increased from…

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Q: In the laboratory a student finds that it takes 1Joules to increase the temperature of 13.3 grams of…

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A: Here we are required to find the specific heat capacity of the unknown metal

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Q: How many joules of energy are required to heat 2.5 kg water from 18.5 to 55.0 Celsius?

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Q: A sample of water of unknown mass undergoes a temperature change from 68.09°C to 72.61°C with a…

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A: Given;

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A: Given: Heat capacity of calorimeter = 15.4 J/oC Initial temperature of calorimeter and water = 21.5…

Q: In the laboratory a student finds that it takes 14.8 Joules to increase the temperature of 10.6…

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A: Given, For metal  Mass of metal (mmetal) = 128.1 g Specific heat of metal (Cpmetal) = ? Initial…