A 12 mm diameter bolt is used to create a lap joint between two plates as shown below. If the allowable shear stress of the material that makes up the plates is 35 MPa, determine the maximum force P that can be resisted by this joint without shear-out failure occurring in the top plate. Enter the calculated Pin kN correct to 3 significant digits below. You only need to consider shear-out failure mode for the top plate. 20 mm Your Answer: Answer units 15 mm P 50 mm
Q: 150 mm P 75 mm 30° P'
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- 1-69.M Figure P1-69 shows a bolt subjected to a tensile load. One failure mode would be if the circular shank of the bolt pulled out from the head, a shearing action. Compute the shear stress in the head for this mode of failure if a force of 22.3 kN is applied. Applied force Shear area Reaction force on underside of head Cylindrical shear area 19.0 mm 8.00 mm -12.0 mm M12 x 1.75 thread3- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point. Q3: The yoke-and-rod connection is subjected to a tensile force of 15 kN. Determine the average normal stress in each rod and the average shear stress in the pin A between the members. Finally, find the shear strain in pin A. Take G steel= 75GPA 40 mm 15 kN. 30 mm 30 mm 15 kN 04: In figure as shown below, assume that a 35mm diameter rivet joint the plates which are each 150mm wide. (a) if the allowable stresses 200 MPa for bearing in the plate material and 120 MPa for shearing of the rivet, determine the minimum thickness of each plate. (b)Under the conditions specified in part (a) what is the largest average stress in the plate. 35mm1. We can visualize the factor of safety for an arbitrary stress using a surface in principal stress space. For a ductile material that yields according to a von Mises criterion with a yield stress σy, sketch the von Mises surface in σ₁ - 02 space and sketch the stress surface that corresponds to a factor of safety FoS = 2. For a brittle material that yields according to a max normal (Rankine) criterion with a tensile strength Gyt and a compressive strength σvc = 20yt, sketch the yield surface and the surface that corresponds to a factor of safety FoS = 2.
- estion 11 62.5 mm Кey 55° The cast iron block with cross-sectional dimensions of 62.5 mm by 62.5 mm consists of two pieces. The pieces are prevented from sliding along the 55° inclined joint by the steel key, which is 62.5 mm long. The working stresses are 275 MPa for cast iron in bearing and 345 MPa for the key in shear. If the block is loaded with P = 256 kN, calculate the required dimension "h" of the key. Write your final answer in 2 decimal places with the unit of mm.Q1/ A bracket is supported by means of 4 rivets of the same size. Design the 7. Alalkau diameter of the rivet if Ou (tenşile ultimate stress) for the rivet material is 560MPA. Which of the rivet has max resistance? 20KN 20KN B0mm 30 mm 30 mm 30 mmpls find box ur answer Determine the value of the von Mises stress at point A. The von Mises stress at point A is This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold- drawn steel and is loaded by the forces F= 0.55 kN, P = 4 kN, and T = 25 N-m. Given: Sy= 280 MPa. 5 15-mm D. 100 mm- MPa.
- In the clevis shown in Fig. 1-11b, find the minimum bolt diameter and the minimum thickness of each yoke(t=10mm) that will support a load P = 63KN without exceeding a shearing stress of 38MPa and a bearing stress of 138Mpa. 1' Figure 1-11bestion 9 P 62.5 mm Key 55° The cast iron block with cross-sectional dimensions of 62.5 mm by 62.5 mm consists of two pieces. The pieces are prevented from sliding along the 55° inclined joint by the steel key, which is 62.5 mm long. The working stresses are 275 MPa for cast iron in bearing and 345 MPa for the key in shear. If the block is loaded with P = 272 kN, calculate the required dimension "b" of the key. Write your final answer in 2 decimal places with the unit of mm.Shown is the stress-strain curve developed from the tension test of a metal alloy bar. The specimen used to develop the stress-strain curve has a round cross-section with a diameter of d = 7 mm and a gauge length of L = 370 mm. Determine the load that must be applied to the specimen to stress the specimen to it's 0.2% offset yield. Express your answer in kN to the nearest whole kN. Your written solution must also include the length of the specimen when stressed to the 0.2% offset yield stress. σ (MPa) 700 600 500 400 300 200 100 0 0.02 0.04 0.06 0.08 0.10 0.002 0.004 0.006 0.008 0.010 € (mm/mm) P d
- After recording the applied twisting moment and resulted angle, fill the following table MT (N.m) T. MPa (degree) (rad.) Now, the twisting moment-twisting angle and shear stress-shear strain curves can be plotted, then determine maximum shear stress, shear stress at proportional limit and modulus of rigidity. 4-6 Problem The following torsion test data were obtained for AA6061-T6 aluminum alloy has a round cross section with 30mm outer diameter, 0 inner diameter and 100 length. 0 32 130 Twisted angle (): 0 1 Torque (N.m): 286 347 487 5.5 591 786 910 1105 1163 1235 1222 3.5 6.5 7.5 9. 10.5 13.5 16.5 21.5 25.5 > Plot the torque-twisted angle curve and determine the proportional limit on it. Plot the shear stress-strain curve the determine the shearing strength and modulus of rigidity. Prof. Adnan N. Abood Asst. Lec. Zainah Waheed 25Answer p1 and Part 2: Determine the shear force acting at each of the following locations:(a) x = 11.0- ft (i.e., just to the left of point B)(b) x = 11.0+ ft (i.e., just to the right of point B)(c) x = 28.5 ftNote that x = 0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.Answers: a) V = ____ kips b) V = ____ kips c) V = ____ kips Part 3: Determine the bending moment acting at each of the following locations:(a) x = 11.0 ft (i.e., at point B)(b) x = 28.5 ftNote that x = 0 at support A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2. Answers: a) M = ____ kips-ft b) M = ____ kips-ft Part 4: Use your shear-force and bending-moment diagrams to determine the maximum bending moment, Mmax, and its location, xmax. Use the bending-moment sign convention detailed in Section 7.2.Answers: Mmax = ____ kips-ft xmax = ____ ftThe plate of the figure is subjected to a bending moment with irregular cycles, which are repeated. In the graphic one of this cycles is represented in terms of stress which appears in each section whose height is h. The piece is made of ductile steel. Determine the number of repetitions of the sequence which the piece can resist before the failure takes place due to fatigue considering a reliability of 95 %. Data: Sult = 1.000 MPa Syp 3D800 Mра thickness e = 4 mm H = 10 cm h = 5 cm r=1 cm ka = 0,72 kp = 0,95 S(MPa) M 400 h 300 200 100 W -100 -200