a)10mmIG mmIG mm1050 mmI6 mm16 mm250 mmT300 mm 2.1) detemine the distance of the centroidal axis (or neutral axis, NA) trom thebase or bottom of the section;2.2) determine the value of the moment of inertia about the neutral axis (Ina); and,2.3) determine the value of the moment of inertia about the base or bottom of thesection (k:).

Answered: Image /qna-images/answer/8a9d5a12-842b-47f2-a81f-51e5f23081fd.jpg

Answered: a) 10mm IG mm IG mm 1050mm IG mm 16mm…

Engineering

Mechanical Engineering

a) 10mm IG mm IG mm 1050mm IG mm 16mm 250 mm 300 mm

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter9: Moments And Products Of Inertia Of Areas

Section: Chapter Questions

Problem 9.4P: The moment of inertia of the plane region about the x-axis and the centroidal x-axis are Ix=0.35ft4...

See similar textbooks

Related questions

Q: (B) What is the meaning of each the following :(choose four only) 1. Synthesis 2.Nanostructured…

A: Given Data⇒ Nano structured Materials Composite Materials Environment-friendly Materials A.S.M,E…

Q: 0.1 mm gap 20 Figuro 0

A: For solution refer below images.

Q: 230 mm 60 mm 25y

Q: 90mm 60mm 45mm R15mm

A: Let’s divide the given section into 3 sections. Section 1 is a rectangular OABC. Section 2 is the…

Q: please answer part g last part

Q: 12)Among the following, which technique can be used for 3D deformation measurement purpose? Ruller…

Q: Determine the forces in members EF and GI of the truss shown.

A: Determine Reactions at B and J Take moment about B

Q: 250 mm 100mm 100 mm to (S0 nm 120 mm FRONT VIEW 160 mn 100 mm 200 m TOP VIEW

Q: 30o0mm*300 mmXJ0omm

A: Given data :- 300mm × 300mm × 300mm Compare L × b × h Here L= length b= width…

Q: nm ha

Q: 300 mm 30º 300 mm 300 mm Can someone please label the projection of F and the rest of the…

Q: How many milligrams are in 0.250 mmole CHC16H1-N2HNS2 (A.wt: C=12, H=1, N=14, S-32)

A: Given values, Atomic weight of C=12, H=1, N=14, S=32 As per the given question the atomic weight of…

Q: 250 mm K3 rad/S 300 300 mm 400 mm

A: AS PER THE POLICY OF THE COMPANY, ONLY FIRST 3 SUBPARTS WILL BE ANSWERED. KINDLY POST REST OF THE…

Q: ACTIVITY 6: LINE TYPES ft. a Simple Object Dimension line (Thin) 8 cm Extension line 5 mm THK (Thin)

A: Defined the types of lines as follows. Center Lines Extension Lines Dimension Lines Cutting Plane…

Q: 6 Which one of the following semi-destructive technique is used for measuring residual stress? a)…

Q: 100 mm 100 mm

A: GivenP=9kNd=6mm

Q: 12 MPа 46 MPа 19 MPа

A: Given:σx=-46 MPaσy=12 MPaζxy=19 MPa

Q: Which of the following is a digital transducer

A: A. Strain gauge It is in the form of strip which is used to measure strain of a body. Change in…

Q: Amplitude of vibration is The displacement of the wave the longest displacement of the particles of…

Q: Define and briefly describe the following notation used on engineering drawings. TYP; EQL SP; 3X

A: TYP The term typical dimension is abbreviated as TYP. The dimensions of the numerous part features…

Q: A 20 in. 5 in. B Ug = 6 in./s Ag = 3 in./s²

A: here we have

Q: 0.9 kips 1.8 kips 1.8 kips 0.9 kips B C 9 ft E F G 12 ft 14 ft→14 ft→ 31.5 ft 8 ft's t

Q: very valuable fx anand fy

Q: Prompts Submitted Answers Die Choose a match The solid, cylindrical metal stock that is pushed…

Q: - 100 mm 20 mm yo 140 mm -20 mm 20 mm - 100 mm

A: Rectangle Area (mm2) x¯ (in) y¯ (in) x¯y¯A (in4) I 2000 -50 70 -7000000 II 2400 0 0 0 III 2000…

Q: 1 MPA = 295.3 inch Hg QUESTION: CONVERT MPag to inch Hg 1 MPag = _________ inch Hg

A: Given question can be solved by the knowledge of conversion units such as :- 》 Atmospheric pressure…

Q: 20MM 40MM 20MM

A: find centroid of the shaded area

Q: 300 mm 150 mm 150 mm 75 mm 100 mm 100 mm

Q: Select one: O a. 88 (N.m] Ob 112 (N.m) Oc.68 (N.m] Od. 86 [N.m]

A: Solution : - Given data : F = ( -20i^ +20j^ + 15k^ ) N

Q: 6 mm 55 mm 10 mm

A: Impact loads are those loads that are acting for a short span of time. Toughness is defined as the…

Q: Find Mo 200N 450Mm 63mm din

Q: c. PH 2. It is comp a. I C. Ar 3. Som a scr a. С. РЕ 4. It is u a. с. LF 5. It is u a.

A: Since you have posted multiple independent questions in a single question we will solve the first…

Q: Determine the CG. Datum 80 in 60 in 40 in A=100 lbs B=200 Ibs C=100 lbs D=100 Ibs

Q: 3mm Imm 2mm 2mm 2mm

A: Let us divide the given figure into 3 sections as shown below – Section 1 is OBCO which is a…

Q: 1MPA = 1N/mm? Select one: True False

A: Given that , 1MPa =1 N/mm

Q: 130) What is the sensitivity of the vernier caliper? A) 0.05mm B) 0.0001mm C) 0.001mm D) 0.01mm E)…

A: (A) 0.05 mm (A) lead (D) Quality control

Q: Fr=6000N Fa=3000N N=2400rpm

A: As Given in Question :- Fr=6000N Fa=3000N N=2400rpm

Q: 5. How do point loads and uniform distributed load be represented in SFD? a) Horizontal lines and…

A: Option c is correct.

Q: diameter of all pins is 5mm Front view • (MPa) 22mm 600 so0 180mm 120mm 0.001 0.01 top view

A: This is a case of elastic deformation of the member BD, so from the stress strain curve we can…

Q: b. Classify each of the following materials as to whether it is a metal, ceramic, or polymer.…

A: Brass – Metal (Alloy) Magnesium oxide (MgO) – Ceramic Plexiglas – Polymer Polychloroprene – Polymer…

Q: 55mm 0mm R2 R1 5mm Omm 13mm H P=20 15mm A B

A: This question can be addressed by first displaying the plate with opening in APDL. The orders for…

Q: A thermoformed disc ending at a diameter of 2 cm and a thickness of 1 cm started from a disc with a…

A: Thermoforming is a general word for a procedure that starts with an extruded plastic sheet. The…

Q: aded (pink) arec 68 mm 68 mm 68 mm 68 mm 68 mm 68 mm 98740460 X mm4 mm4 mm mm

Q: 10 in 11 in 10 in A 20 kips 35 kips 81 kips Tmis not your Gwn phoperty so do rat use in anny way as…

A: from Given diagram-

Q: 4 kips/ft 1B 5 ft- 2 ft 2 ft 8 kins 8 kins

A: The loading diagram of the beam is shown as follows, Let's draw the free body diagram of the beam,

Concept explainers

Free undamped vibrations

Whenever an object/system displaces in either side of its equilibrium position with the help of an external/internal means, then the object/system moves regularly or randomly on both sides of its equilibrium position. This motion is called vibration. Generally, there are three types of vibration: longitudinal vibration, transverse vibration, and torsional vibration.

Question

a)
10mm
IG mm
IG mm
1050 mm
I6 mm
16 mm
250 mmT
300 mm

2.1) detemine the distance of the centroidal axis (or neutral axis, NA) trom the
base or bottom of the section;
2.2) determine the value of the moment of inertia about the neutral axis (Ina); and,
2.3) determine the value of the moment of inertia about the base or bottom of the
section (k:).

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

For a beam with the cross-section shown, calculate the moment of inertia about the z axis. Assume the following dimensions: by-83mm h₂ = 15 mm by 9 mm b₂-72 mm by-35 mm h-24 mm The centroid of the section is located 65 mm above the bottom surface of the beam. M₂ H Answer: mm by
Find the moment of inertia of the given lamina about X-X axis passing through its centroid, where b1=110 mm, d1=38 mm, b2= 70 mm & d2=100mm. b2 d2 TP b1 (i) The X value is (unit is in mm) = (i) The Y value is (unit is in mm) = (iii) the Ixx1 value is (unit is in mm4)= (iv) the Ixx2 value is (unit is in mm4)= (v) The Ixx value is (unit is in mm4)=
Find the moment of inertia (ly) of the given lamina about Y-Y axis passing through its centroid, where b1=108 mm, d1=38 mm, b2= 62 mm & d2=84mm. (enter only the values in the boxes by referring the units given in bracket) b2 TP b1 O The X value is (unit is in mm) = O The Y value is (unit is in mm) (i) the lyyi value is (unit is in mm)= (iv) the lyy2 value is (unit is in mm)= . (V) The lyy value is (unit is in mm4)=
Find the moment of inertia of the given lamina about X-X axis passing through its centroid, where b1=110 mm, d1=38 mm, b2= 70 mm & d2=100mm. (enter only the values in the boxes by referring the units given in bracket) b2 TP b1 (i) The X value is (unit is in mm) = (i) The Y value is (unit is in mm) = (iii) the Ixx1 value is (unit is in mm4)= (iv) the Ixx2 value is (unit is in mm4) = (v) The Ixx value is (unit is in mm4)=
Determine the moment of inertia, about the centroidal axis (EC) parallel to the x-axis, in in.⁴. b = 8 in., d = 9 in. and t = 0.9 in.
Q2: Determine the moment of inertia of the area about the x – axis. Solve the problem in two ways, using rectangular differential elements: (a) having a thickness of dx, and (b) having a thickness of dy. -y = 4 - 4x2 4 in. 1 in. 1 in.
4.) Find the moment of inertia about the indicated x-axis for the shaded area. r=4cm 10cm
Q4- Determine the moment of inertia of the shaded area shown in figure with respect to(x) axis? (A3) 3 cm (A2) (A1) 3 cm 3 cm 4 cm x
Question 1 Find (a) the location of the centroid (x, y); (b) the area moment of inertia about the global x axis, k; and (c) the area moment of inertia about the global y axis, ly. *- 3.67 mm; ỹ - 21.5mm Ixs 4.3x10* mm" ; Ty: 1.Sxlo* mm 5mm 13 mm Somm 13 10 Mm mm MM Mm
Find the moment of inertia (ly) of the given lamina about Y-Y axis passing through its centroid, where b1=114 mm, d1=33 mm, b2= 50 mm & d2=86mm. of (enter only the values in the boxes by referring the units given in bracket) b2 stion d2 d1 b1
Determine the moment of inertia about the x- and y-axes both passes through the centroid the section shown. a = 10 mm. y 12 mm | 8 mm r2-6 mm (3) (5) 3 mm (4) ri=2 mm (2) 3 mm (1) a ..... .....
Determine the principle moments of inertia and the orientation of the principle axes for the section shown below. Units are in millimeters and centroid of the section is given. Use the given partition for areas. Hint: I = I, due to the symmetry. Draw the Mohr's circle for the moments of inertia show principle axes. to- C(ag); centroid 20 X =j = 8,33 20 I, + 1, (1, -ly (1, – 1,)/2 tan 20, + Iy