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A 10kg block sits stationary on the ground. 130N of forward force is applied to it. The coefficient of friction between the block and the ground is 0.8 a. What is this block's acceleration? b. How long will it take this block to move 20m? c. How fast will this block be moving after it has travelled 20m?

A 10kg block sits stationary on the ground. 130N of forward force is applied to it. The coefficient of friction between the block and the ground is 0.8 a. What is this block's acceleration? b. How long will it take this block to move 20m? c. How fast will this block be moving after it has travelled 20m?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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A 10kg block sits stationary on the ground. 130N of forward force is applied to it. The coefficient of friction between the block and the ground is 0.8 a. What is this block's acceleration? b. How long will it take this block to move 20m? c. How fast will this block be moving after it has travelled 20m?
Transcribed Image Text:A 10kg block sits stationary on the ground. 130N of forward force is applied to it. The coefficient of friction between the block and the ground is 0.8 a. What is this block's acceleration? b. How long will it take this block to move 20m? c. How fast will this block be moving after it has travelled 20m?
Expert Solution
Step 1

a.

From Newton's law

Fnet=Fapp-Ff⇒ma=Fapp-μmg⇒a=Fapp-μmgm

Substitute

a=130 N-0.8×10 kg×9.8 ms210 kg=5.16 ms2

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