USE PYTHON TO SOLVE A 1000-lb weight is supported by 3 cables as shown in the figure. Note that cable #3 is attached alongthe y-axis, at a distance of d feet from the origin, O. The static equilibrium equations for this structure areT₁5√33T₁71583T₁ +T₂ 0T₂ +dLT3√15810√158where L = √10² + d², length of cable 3Given d= 5 ft, write a script in PYTHON to solve for the three tensionssimultaneously using solve function from NumPy linalg submodule.Use a formatted statement to write your answer to the screen.= 010T₂ + T3-1000 = 0Lx44'(-)O10'2d1000 lb3'y

In this question we have to write a python code for the given image description.Let's code and hope this helps, If you have any queries please utilize threaded question feature.Algorithm:1# Given data 2d = 5 # feet 3L = square_root(10^2 + d^2) 4 5# Coefficients of the static equilibrium equations 6A = [ 7 [2/square_root(33), -7/square_root(158), 0], 8 [-2/square_root(33), -3/square_root(158), d/L], 9 [5/square_root(33), 10/square_root(158), 10/L] 10] 11 12# Right-hand side of the equations 13B = [0, 0, 1000] 14 15# Solve the system of equations 16T = solve_linear_system(A, B) 17 18# Output the results 19print("T1 =", T[0], "lb, T2 =", T[1], "lb, T3 =", T[2], "lb")Explanation:The requirement is to solve a system of linear equations representing static equilibrium conditions in a physical system.The system involves three unknown tension forces (T1, T2, T3) in a structure. The coefficients of the equations and the right-hand side values are set up using NumPy arrays.The code uses NumPy's `linalg.solve` function to find the tension forces, and finally, it prints the results. The physical system is not explicitly described, but it appears to involve forces and lengths, possibly in a static equilibrium scenario.Code:1import numpy as np 2 3# Given data 4d = 5 # feet 5L = np.sqrt(10**2 + d**2) 6 7# Coefficients of the static equilibrium equations 8A = np.array([ 9 [2/np.sqrt(33), -7/np.sqrt(158), 0], 10 [-2/np.sqrt(33), -3/np.sqrt(158), d/L], 11 [5/np.sqrt(33), 10/np.sqrt(158), 10/L] 12]) 13 14# Right-hand side of the equations 15B = np.array([0, 0, 1000]) 16 17# Solve the system of equations 18T = np.linalg.solve(A, B) 19 20print(f"T1 = {T[0]:.2f} lb, T2 = {T[1]:.2f} lb, T3 = {T[2]:.2f} lb")Output: