A 1000 kVA, 6.6kV, 3-phase, star-connected alternator has a field resistance of 0.50 ohm per phase and an armature resistance of 0.05 ohm per phase. The field current at full load at 0.85 pf lagging is 200A. The stray power loss is 84kW. Calculate the efficiency at full load 0.90 pf lagging.
A 1000 kVA, 6.6kV, 3-phase, star-connected alternator has a field resistance of 0.50 ohm per phase and an armature resistance of 0.05 ohm per phase. The field current at full load at 0.85 pf lagging is 200A. The stray power loss is 84kW. Calculate the efficiency at full load 0.90 pf lagging.
Introductory Circuit Analysis (13th Edition)
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![A 1000 kVA, 6.6kV, 3-phase,
star-connected alternator has
a field resistance of 0.50 ohm
per phase and an armature
resistance of 0.05 ohm per
phase. The field current at full
load at 0.85 pf lagging is
200A. The stray power loss is
84KW. Calculate the efficiency
at full load 0.90 pf lagging.
use two decimal places if the
answer is not exact and do not
include the unit anymore.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdde8f58a-ade0-4097-a5ac-5ecdc889449b%2Fdb59bf99-ddad-4fb5-91b8-5ab5af66e519%2Fwibzmd_processed.png&w=3840&q=75)
Transcribed Image Text:A 1000 kVA, 6.6kV, 3-phase,
star-connected alternator has
a field resistance of 0.50 ohm
per phase and an armature
resistance of 0.05 ohm per
phase. The field current at full
load at 0.85 pf lagging is
200A. The stray power loss is
84KW. Calculate the efficiency
at full load 0.90 pf lagging.
use two decimal places if the
answer is not exact and do not
include the unit anymore.
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