A 1000 Kg sports car accelerates from 0 to 30m/s in 10 s. What is the average power of the engine?

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**Problem 7: Calculating Average Power of an Engine**

A 1000 kg sports car accelerates from 0 to 30 m/s in 10 seconds. What is the average power of the engine?

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To solve this problem, consider applying the principles of physics related to acceleration, work, and power.

**Steps to Solve:**

1. **Calculate the acceleration (a):**  
   Use the formula:  
   \[ a = \frac{{v_f - v_i}}{t} \]  
   where \( v_f = 30 \text{ m/s} \), \( v_i = 0 \text{ m/s} \), and \( t = 10 \text{ s} \).

2. **Determine the work done (W):**  
   The work done on the car is equal to the change in kinetic energy:  
   \[ W = \Delta KE = \frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2 \]  
   where \( m = 1000 \text{ kg} \).

3. **Calculate the average power (P):**  
   Power is the work done per unit time, calculated with:  
   \[ P = \frac{W}{t} \]  

By following these steps, you can determine the average power output of the engine over the 10-second interval.
Transcribed Image Text:**Problem 7: Calculating Average Power of an Engine** A 1000 kg sports car accelerates from 0 to 30 m/s in 10 seconds. What is the average power of the engine? --- To solve this problem, consider applying the principles of physics related to acceleration, work, and power. **Steps to Solve:** 1. **Calculate the acceleration (a):** Use the formula: \[ a = \frac{{v_f - v_i}}{t} \] where \( v_f = 30 \text{ m/s} \), \( v_i = 0 \text{ m/s} \), and \( t = 10 \text{ s} \). 2. **Determine the work done (W):** The work done on the car is equal to the change in kinetic energy: \[ W = \Delta KE = \frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2 \] where \( m = 1000 \text{ kg} \). 3. **Calculate the average power (P):** Power is the work done per unit time, calculated with: \[ P = \frac{W}{t} \] By following these steps, you can determine the average power output of the engine over the 10-second interval.
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