A 100.0-mL sample of spring water was treated to convert any iron present to Fe2*. Addition of 25.00-mL of 0.002517 M K2C12O7 resulted in the reaction 6 Fe²* + Cr2O7²- + 14 H* → 6 Fe* + 2 Cr³+ + 7 H;O The excess K:Crz07 was back-titrated with 8.53 mL of 0.00949 M Fe²* solution. Calculate the concentration of iron in the sample in parts per million.

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2. A 100.0-mL sample of spring water was treated to convert any iron present to Fe2*.
Addition of 25.00-mL of 0.002517 M K2C12O7 resulted in the reaction
6 Fe2* + Cr2O7?- + 14 H* → 6 Fe³+ + 2 Crt + 7 H2O
The excess K2Cr2O7 was back-titrated with 8.53 mL of 0.00949 M Fe² solution. Calculate
the concentration of iron in the sample in parts per million.
Transcribed Image Text:2. A 100.0-mL sample of spring water was treated to convert any iron present to Fe2*. Addition of 25.00-mL of 0.002517 M K2C12O7 resulted in the reaction 6 Fe2* + Cr2O7?- + 14 H* → 6 Fe³+ + 2 Crt + 7 H2O The excess K2Cr2O7 was back-titrated with 8.53 mL of 0.00949 M Fe² solution. Calculate the concentration of iron in the sample in parts per million.
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