A 100.0-mL sample of spring water was treated to convert any iron present to Fe. Addition of 25.00-mL of 0.002517 M K₂Cr₂O, resulted in the reaction 6Fe²+ + Cr₂O + 14H* 6Fe³+ + 2Cr³+ + 7H₂O The excess K₂Cr₂O, was back-titrated with 8.53 mL of 0.00949 M Fe²+ solution. Calculate the concentra- tion of iron in the sample in parts per million.
A 100.0-mL sample of spring water was treated to convert any iron present to Fe. Addition of 25.00-mL of 0.002517 M K₂Cr₂O, resulted in the reaction 6Fe²+ + Cr₂O + 14H* 6Fe³+ + 2Cr³+ + 7H₂O The excess K₂Cr₂O, was back-titrated with 8.53 mL of 0.00949 M Fe²+ solution. Calculate the concentra- tion of iron in the sample in parts per million.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A 100.0-mL sample of spring water was treated
to convert any iron present to Fe. Addition of
25.00-mL of 0.002517 M K₂Cr₂O, resulted in the
reaction
6Fe²+ + Cr₂O + 14H*
6Fe³+ + 2Cr³+ + 7H₂O
The excess K₂Cr₂O, was back-titrated with 8.53 mL
of 0.00949 M Fe²+ solution. Calculate the concentra-
tion of iron in the sample in parts per million.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51c62255-3f0f-4a0e-8f49-60d53adbb28c%2F6f28d705-b729-4810-955b-1d4075909d16%2Fvh5fhre_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 100.0-mL sample of spring water was treated
to convert any iron present to Fe. Addition of
25.00-mL of 0.002517 M K₂Cr₂O, resulted in the
reaction
6Fe²+ + Cr₂O + 14H*
6Fe³+ + 2Cr³+ + 7H₂O
The excess K₂Cr₂O, was back-titrated with 8.53 mL
of 0.00949 M Fe²+ solution. Calculate the concentra-
tion of iron in the sample in parts per million.
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