A 100.0-mL aliquot of 0.100 M diprotic acid H₂A (pK₁ = 4.00, pK₂ = 8.00) was titrated with 1.00 M NaOH. At what volumes are the two equivalence points? Find the pH at the following volumes of base added (V) and sketch a graph of pH versus V: 0, 5.0, 10.0, 15.0, 20.0, and 22.0 mL.

A 100.0-mL aliquot of 0.100 M diprotic acid H₂A (pK₁ = 4.00, pK₂ = 8.00) was titrated with 1.00 M NaOH. At what volumes are the two equivalence points? Find the pH at the following volumes of base added (V) and sketch a graph of pH versus V: 0, 5.0, 10.0, 15.0, 20.0, and 22.0 mL.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

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A 100.0-mL aliquot of 0.100 M diprotic acid H₂A
(pK₁ = 4.00, pK2 = 8.00) was titrated with 1.00 M NaOH. At
what volumes are the two equivalence points? Find the pH at
the following volumes of base added (V) and sketch a graph
of pH versus V₁: 0, 5.0, 10.0, 15.0, 20.0, and 22.0 mL.

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Step 1: Addition of 0.00 mL of NaOH

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Step 2: Addition of 5.0 mL of NaOH

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Step 3: Addition of 10.0 mL of NaOH

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Step 4: Addition of 15.0 mL of NaOH

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Step 5: Addition of 20.0 mL of NaOH

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Step 6: Addition of 22.0 mL of NaOH

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Step 7: Additional points

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Step 8: Plot the graph

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