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A 100 mL solution was prepared by dissolving 10.00 g of Cas04 (MW= 136. 14 g/mol) in water. The density of the solution was found to be 1.15 g/ml at 25°C. Find the new boiling and freezing temperature of water in this solution. Answers in 2 decimal places. no need to write the unit. New boiling point = [A] New Freezing point [B]

A 100 mL solution was prepared by dissolving 10.00 g of Cas04 (MW= 136. 14 g/mol) in water. The density of the solution was found to be 1.15 g/ml at 25°C. Find the new boiling and freezing temperature of water in this solution. Answers in 2 decimal places. no need to write the unit. New boiling point = [A] New Freezing point [B]

General, Organic, and Biological Chemistry
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:H. Stephen Stoker
Chapter8: Solutions
Section: Chapter Questions
Problem 8.9EP: A solution is made by dissolving 34.0 g of NaCl in 100 g of H2O at 0C. Based on the data in Table...
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A 100 mL solution was prepared by dissolving 10.00 g of Cas04 (MW= 136. 14 g/mol) in water. The density of the solution was found to be 1.15 g/ml at 25°C. Find the new boiling and freezing temperature of water in this solution. Answers in 2 decimal places. no need to write the unit. New boiling point = [A] New Freezing point [B] %3!
Transcribed Image Text:A 100 mL solution was prepared by dissolving 10.00 g of Cas04 (MW= 136. 14 g/mol) in water. The density of the solution was found to be 1.15 g/ml at 25°C. Find the new boiling and freezing temperature of water in this solution. Answers in 2 decimal places. no need to write the unit. New boiling point = [A] New Freezing point [B] %3!
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