Answered: A 10 wt% aqueous sulfuric acid…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Related questions

Question

A 10 wt% aqueous sulfuric acid solution, ρ = 1.03 g/ml, flows through a 45 m long pipe with a 6 cm inside diameter at a rate of 100 L/min. Determine the

a) molarity of the sulfuric acid in this solution.

b) time (s) it would take to fill a 55 gallon drum.

c) mass of water in the pipe (kg)

d) mass flow rate of water out of the pipe (kg/min)

e) component molar flow rate of H₂SO₄ out of the pipe (mols/min)

Expert Solution

Step 1

Given:

density=1.03 g/ml

(a) take 1 kg of solution=1000 g

$\begin{array}{rcl} v o l u m e o f s o l u t i o n & = & \frac{m a s s}{d e n s i t y} \\ = & \frac{1000}{1.03} \\ = & 0.9709 L \\ i n 1 k g o f s o l u t i o n s u l p h u r i c p r e s e n t & = & \frac{10}{100} * 1 = 0.1 k g = 100 g \\ s u l p h u r i c a c i d m o l e s & = & \frac{m a s s}{m o l e c u l a r w e i g h t} = \frac{100}{98.079} = 1.019 \\ M o l a r i t y & = & \frac{m o l e s o f s u l p h u r i c a c i d}{s o l u t i o n v o l u m e} \\ = & \frac{1.019}{0.9709} \\ = & 1.050 M \end{array}$