A 10 mH inductor, a 1 uF capacitor, and a vari- able resistor are connected in parallel in the circuit shown. The resistor is adjusted so that the roots of the characteristic equation are -8000 + j6000 rad/s. The initial voltage on the capacitor is 10 V, and the initial current in the inductor is 80 mA. Find ic lo Answer: (a) 62.5 2: (b) -240,000 V/s: (c) B 10 V, B, = -80/3 V: (d) i(t) = 10e 8 cos 6000t + (82/3) sin 6000r] mA when t 2 0. a) R: b) dv(0")/dt; %3D c) B and Bz in the solution for v; and COS %3D
A 10 mH inductor, a 1 uF capacitor, and a vari- able resistor are connected in parallel in the circuit shown. The resistor is adjusted so that the roots of the characteristic equation are -8000 + j6000 rad/s. The initial voltage on the capacitor is 10 V, and the initial current in the inductor is 80 mA. Find ic lo Answer: (a) 62.5 2: (b) -240,000 V/s: (c) B 10 V, B, = -80/3 V: (d) i(t) = 10e 8 cos 6000t + (82/3) sin 6000r] mA when t 2 0. a) R: b) dv(0")/dt; %3D c) B and Bz in the solution for v; and COS %3D
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Question
![A 10 mH inductor, a 1 uF capacitor, and a vari-
able resistor are connected in parallel in the
circuit shown. The resistor is adjusted so that
the roots of the characteristic equation are
-8000 + j6000 rad/s. The initial voltage on the
capacitor is 10 V, and the initial current in the
inductor is 80 mA. Find
iR
RE
Vo
Answer: (a) 62.5 0:
a) R:
(b) -240,000 V/s:
(c) B= 10 V. By = -80/3 V:
(d) i,(t) = 10e NOXorT8 cos 6000t
+ (82/3) sin 6000r] mA when t 2 0.
b) dv(0")/dt:
c) B and B, in the solution for v; and
d) i(1).
DELL
AESICOFT
CiT](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a89195c-e549-4a08-ae2c-9d32d74fa09c%2Fb4b57c7b-70f3-4a54-988b-dac7917954d1%2Fxeryree_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 10 mH inductor, a 1 uF capacitor, and a vari-
able resistor are connected in parallel in the
circuit shown. The resistor is adjusted so that
the roots of the characteristic equation are
-8000 + j6000 rad/s. The initial voltage on the
capacitor is 10 V, and the initial current in the
inductor is 80 mA. Find
iR
RE
Vo
Answer: (a) 62.5 0:
a) R:
(b) -240,000 V/s:
(c) B= 10 V. By = -80/3 V:
(d) i,(t) = 10e NOXorT8 cos 6000t
+ (82/3) sin 6000r] mA when t 2 0.
b) dv(0")/dt:
c) B and B, in the solution for v; and
d) i(1).
DELL
AESICOFT
CiT
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