A 10-kg mass is attached to a spring, stretching it 0.7 m from its natural length. The mass is started in motion from the equilibrium position with an initial velocity of 1 m/sec in the upward direction. Find the distance at t=0.5 sec, if the force due to air resistance is -90v N. The initial conditions are x(0) = 0 (the mass starts at the equilibrium position) and i(0) = -1 (the initial velocity is in the negative direction). Use 4 decimal palces.

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter10: Virtual Work And Potential Energy
Section: Chapter Questions
Problem 10.57P: Find the stable equilibrium position of the system described in Prob. 10.56 if m = 2.06 kg.
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A 10-kg mass is attached to a spring, stretching it 0.7 m from its natural length. The mass is started in motion from the equilibrium
position with an initial velocity of 1 m/sec in the upward direction. Find the distance at t=0.5 sec, if the force due to air resistance
is -90v N. The initial conditions are x(0) = 0 (the mass starts at the equilibrium position) and i(0) = -1 (the initial velocity is in the
negative direction). Use 4 decimal palces.
Transcribed Image Text:A 10-kg mass is attached to a spring, stretching it 0.7 m from its natural length. The mass is started in motion from the equilibrium position with an initial velocity of 1 m/sec in the upward direction. Find the distance at t=0.5 sec, if the force due to air resistance is -90v N. The initial conditions are x(0) = 0 (the mass starts at the equilibrium position) and i(0) = -1 (the initial velocity is in the negative direction). Use 4 decimal palces.
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