-A 10 kg block is pulled up an incline at an angle of 60° with a force of 40 N. The Eape coefficient of kinetic friction between the block and the incline is 0.3. a. Draw a free body diagram. b. F. app mg case/60 mgsing FK Find the block's acceleration. Use g = 10 m/s² O 0 ΣFy = may >>> FN-mgcase may → FN = mgcose FN = (100) cos 60 = 50 EFX = max → Fapp-masine - FK= max → Fapp-masino - MK FN = ma ->> mr Formasing-HK FN 40-100sin 60- (0.3x50) m
-A 10 kg block is pulled up an incline at an angle of 60° with a force of 40 N. The Eape coefficient of kinetic friction between the block and the incline is 0.3. a. Draw a free body diagram. b. F. app mg case/60 mgsing FK Find the block's acceleration. Use g = 10 m/s² O 0 ΣFy = may >>> FN-mgcase may → FN = mgcose FN = (100) cos 60 = 50 EFX = max → Fapp-masine - FK= max → Fapp-masino - MK FN = ma ->> mr Formasing-HK FN 40-100sin 60- (0.3x50) m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![- A 10 kg block is pulled up an incline at an
angle of 60° with a force of 40 N. The
Eape
coefficient of kinetic friction between the
block and the incline is 0.3.
a. Draw a free body diagram.
b.
F₂
->>
→
app
my case co
Find the block's acceleration. Use g = 10
m/s²
O
0
ΣFy = may
EFX = max
>>> FN-mgcose= may → FN = mgcose FN = (100) cos 60 = 50
Fapp-masine - FK= max → Fapp-masino - MK FN = ma
40-100sin 60- (0.3x50)
FORR
-masing-HK FN
mgsing
FK
m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F05ba23d1-cd3b-4e79-b55e-74c333e8fb4e%2F2cdd6a9d-2341-46b1-9cdd-326906e3c815%2Ftw8oxgr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:- A 10 kg block is pulled up an incline at an
angle of 60° with a force of 40 N. The
Eape
coefficient of kinetic friction between the
block and the incline is 0.3.
a. Draw a free body diagram.
b.
F₂
->>
→
app
my case co
Find the block's acceleration. Use g = 10
m/s²
O
0
ΣFy = may
EFX = max
>>> FN-mgcose= may → FN = mgcose FN = (100) cos 60 = 50
Fapp-masine - FK= max → Fapp-masino - MK FN = ma
40-100sin 60- (0.3x50)
FORR
-masing-HK FN
mgsing
FK
m
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