A 1.5mm surface is being measured on an interferometer. A lamp is used which can emit wave lengths as follows. Red: 0.842 um, Blue: 0.6628 um. What are the nominal fractions expected for the gauge for the two wave lengths? Choices:- b) For Blue light, Nf = 0.3568 For red light, Nf = 1.2589 a) For Blue light, Nf = 0.2222 For red light, Nf = 0.9999 c) For Blue light, Nf = 0.2523 For red light, Nf = 0.9454 d) For Blue light, Nf = 0.2666 For red light, Nf = 35.9454
A 1.5mm surface is being measured on an interferometer. A lamp is used which can emit wave lengths as follows. Red: 0.842 um, Blue: 0.6628 um. What are the nominal fractions expected for the gauge for the two wave lengths? Choices:- b) For Blue light, Nf = 0.3568 For red light, Nf = 1.2589 a) For Blue light, Nf = 0.2222 For red light, Nf = 0.9999 c) For Blue light, Nf = 0.2523 For red light, Nf = 0.9454 d) For Blue light, Nf = 0.2666 For red light, Nf = 35.9454
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Question:-
A 1.5mm surface is being measured on an interferometer. A lamp is used which can emit wave
lengths as follows. Red: 0.842 um, Blue: 0.6628 um. What are the nominal fractions expected for the
gauge for the two wave lengths?
Choices:-
b) For Blue light, Nf = 0.3568 For red light, Nf = 1.2589
%3D
a) For Blue light, Nf = 0.2222 For red light, Nf = 0.9999
c) For Blue light, Nf = 0.2523 For red light, Nf = 0.9454
%3D
d) For Blue light, Nf = 0.2666 For red light, Nf = 35.9454](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92319cff-7a53-4879-b88e-6ce18df1c00b%2F5aba200f-a44b-40d2-bbab-4c24a1481e9f%2Fqqasog_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question:-
A 1.5mm surface is being measured on an interferometer. A lamp is used which can emit wave
lengths as follows. Red: 0.842 um, Blue: 0.6628 um. What are the nominal fractions expected for the
gauge for the two wave lengths?
Choices:-
b) For Blue light, Nf = 0.3568 For red light, Nf = 1.2589
%3D
a) For Blue light, Nf = 0.2222 For red light, Nf = 0.9999
c) For Blue light, Nf = 0.2523 For red light, Nf = 0.9454
%3D
d) For Blue light, Nf = 0.2666 For red light, Nf = 35.9454
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