A 1.5m + 1.5m B P₁ = 400 kN E m-1 0.6 m 2.1 m- D 2.4 m P₂ = 360 kN

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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1.5m 1.5 m
P₁ = 400 kN
(a)
E
B
F
Figure Q1
-2.1 m-
0.6 m
D
2.4 m P₂ = 360 kN
Transcribed Image Text:1.5m 1.5 m P₁ = 400 kN (a) E B F Figure Q1 -2.1 m- 0.6 m D 2.4 m P₂ = 360 kN
Q1. The horizontal rigid beam ABCD is supported by vertical bars BE and CF and is
loaded by vertical forces P₁ - 400 KN and P: 360 kN acting at points A and D.
respectively as shown in Figure Q1. Bars BE and CF are made of steel (E-200 GPa)
and have cross-sectional areas Anr-11,100 mm² and Act 9,280 mm². The distances
between various points on the bars are shown in the figure. Determine:-
(a) The free body diagram
(b) The reaction forces in the vertical bar
***
(c) the vertical displacements and op of points A and D, respectively.
Transcribed Image Text:Q1. The horizontal rigid beam ABCD is supported by vertical bars BE and CF and is loaded by vertical forces P₁ - 400 KN and P: 360 kN acting at points A and D. respectively as shown in Figure Q1. Bars BE and CF are made of steel (E-200 GPa) and have cross-sectional areas Anr-11,100 mm² and Act 9,280 mm². The distances between various points on the bars are shown in the figure. Determine:- (a) The free body diagram (b) The reaction forces in the vertical bar *** (c) the vertical displacements and op of points A and D, respectively.
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