A 1.5 kg block initially at rest is launched by a horizontal spring with a spring constant of \( k = 175 \, \text{N/m} \). The spring is initially compressed a distance of 25 cm from equilibrium. After being launched, the block travels toward the top of a frictionless incline and comes to rest after reaching a maximum height \( h \) as shown below. Apply the Conservation of Energy Theorem to determine:a. The object's launch velocity at the spring's point of equilibrium in m/s.b. The maximum height reached by the block (\( h \)) in meters.c. Determine the impulse delivered by the spring in kg-m/s. (Hint: consider the initial and final locations as \( x_i = -25 \, \text{cm} \) and \( x_f = 0 \, \text{cm} \)).d. Determine the average force exerted by the spring on the block (in Newtons) if the time of contact equals 0.185 seconds.e. Determine the average power delivered by the spring in watts.**Diagram Explanation:**- The diagram features a spring attached to a block with a mass of 1.5 kg. The block is launched from a horizontal surface by the compressed spring.- The spring's equilibrium position is marked, and the compression distance is noted as \( x_i = -25 \, \text{cm} \).- The block moves up a frictionless incline and reaches the maximum height \( h \).**List of Numerical Options:**1. 12.232. 0.25473. 2.7004. 24.595. 7.5836. 36.437. 21.898. 29.589. 0.187010. 0.37211. 4.05012. 10.4313. 1.58014. 5.40015. 32.58 **Physics Problem: Spring Launch**A 1.5 kg block initially at rest is launched by a horizontal spring with a spring constant of \( k = 175 \, \text{N/m} \). The spring is initially compressed a distance of 25 cm from equilibrium. After being launched, the block travels toward the top of a frictionless incline and comes to rest after reaching a maximum height \( h \) as shown. Apply the Conservation of Energy Theorem to determine:a. The object's launch velocity at the spring's point of equilibrium in m/s.b. The maximum height reached by the block (\( h \)) in meters.c. Determine the impulse delivered by the spring in kg-m/s. (Hint: consider the initial and final locations as \( x = -25 \, \text{cm} \) and \( x = 0 \, \text{cm} \) ).d. Determine the average force exerted by the spring on the block (in Newtons) if the time of contact equals 0.185 seconds.e. Determine the average power delivered by the spring in watts.**Diagram Explanation:**- The diagram shows a spring with a mass of 1.5 kg attached at the end. The spring is initially compressed by 25 cm. - There is a frictionless incline, and the block ascends this incline to reach a maximum height \( h \).**Multiple Choice Answers:**1. 12.232. 0.25473. 2.7004. 24.595. 7.5886. 36.437. 21.808. 26.589. 0.187010. 0.37211. 4.05012. 10.4313. 1.58014. 5.49015. 32.58

Name: A 1.5 kg block initially at rest is launched by a horizontal spring w
Uploaded: 2024-03-20T06:58:04.000Z
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Description: A 1.5 kg block initially at rest is launched by a horizontal spring with a spring constant of \( k = 175 \, \text{N/m} \). The spring is initially compressed a distance of 25 cm from equilibrium. After being launched, the block travels toward the to