A 1.461 g sample containing K2SO4, NH4Cl, and inert materials was dissolved in sufficient water to give exactly 250 mL of solution. A 25.0 mL aliquot of this solution yielded 0.299 g of precipitate that consisted only of (C6H5)4BK and (C6H5)4BNH4. Another 50.0 mL aliquot of the solution gave 0.3230 g (C6H5)4BK only. Calculate the mass percent of K2SO4 and NH4Cl is the sample

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