A 1.3Kg particle moves from an initial position r1=2i-1j+2k m to a final position r2=6i-4j-4k m while a force F=4i-5j+4k N acts on it. What is the work done by the force on the particle? Answer in Joules

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 1.3Kg particle moves from an initial position r1=2i-1j+2k m to a final position r2=6i-4j-4k m while a force F=4i-5j+4k N acts on it. What is the work done by the force on the particle?

Answer in Joules

Expert Solution
Step 1: Given

Given
straight F equals open square brackets 4 open parentheses straight i close parentheses minus 5 open parentheses straight j close parentheses plus 4 open parentheses straight k close parentheses close square brackets straight N
Initial space position space is space straight r subscript 1 equals open square brackets 2 open parentheses straight i close parentheses minus 1 open parentheses straight j close parentheses plus 2 open parentheses straight k close parentheses close square brackets straight m
Final space space position space is space straight r subscript 2 equals open square brackets 6 open parentheses straight i close parentheses minus 4 open parentheses straight j close parentheses minus 4 open parentheses straight k close parentheses close square brackets straight m


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