A 1.15-kg wooden block rests on a table over a large hole as in the figure below. A 5.30-g bullet with an initial velocity v, is fired upward into the bottom of the block and remains in the block after the collision. The block andbullet rise to a maximum height of 21.0 cm.MCalculate the initial velocity of the bullet from the information provided. (Let up be the positive direction.)Your response differs from the correct answer by more than 10%. Double check your calculations. m/s An object of mass 3.07 kg, moving with an initial velocity of 4.98 î m/s, collides with and sticks to an object of mass 3.07 kg with an initial velocity of -4.07 j m/s. Find the final velocity of the composite object.]j) m/sNeed Help?Watch ItRead It

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3. This problem refers to the figure below: mmm There are 3 identical bobs of mass m hanging side-by-side. Two are then lifted to a height of h and released. The collisions in this problem are elastic. Answer the following questions: (a) Let's call the initial and final state immediately before and after the collision, respectively. Write down the initial momentum and kinetic energy of the system in terms of m and h. (b) Show that, after the collision, the left and center bobs rise to height h while the right bob becomes stationary. In particular, show that the center bob acts as if it were swinging freely as a lone pendulum.
A 27.5-g object moving to the right at 22.0 cm/s overtakes and collides elastically with a 10.5-g object moving in the same direction at 15.0 cm/s.Find the velocity of each object after the collision. (Take the positive direction to be to the right. Indicate the direction with the sign of your answer.) 27.5-g object cm/s 10.5-g object cm/s
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A 70.0 kg ice hockey goalie, originally at rest, has a 0.280 kg hockey puck slapped at him at a velocity of 41.5 m/s. Suppose the goalie and the puck have an elastic collision, and the puck is reflected back in the direction from which it came. What would the final velocities of the goalie and the puck, respectively, be in this case? Assume that the collision is Ugoalie and Upuck completely elastic. Ugoalie Upuck= 0.14 Incorrect -5.38 Incorrect m/s m/s
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In a 2D elastic collision two balls collide (see picture). The 1st balls mass is 50g. It has an initial velocity of 6m/s. The 2nd balls mass is 125g. It has an initial velocity of 0m/s. The 1st ball has a final velocity of 5 m/s and an angle ? = 45°. Find the velocity of the second ball and it’s angle ?.
I. A lump of clay (m = 3.01 kg) is thrown towards a wall at speed v = 3.15 m/s. The lump sticks to the wall. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during this collision. II. Same lump is thrown towards the same wall, but this time it bounces off the wall at speed of 3.15 m/s. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic energy lost during this collision. III. Same lump is thrown towards the same wall, but this time it bounces off the wall at speed of 2.24 m/s. (a) What kind of collision is it? Is momentum conserved during this collision? Why or why not? (b) Calculate the impulse imparted on the lump by the wall. (c) Calculate percent of initial kinetic…
A light ball of mass 14.7g is at rest on table when a heavier ball of mass 26.3g and moving with an initial velocity of 2.01 m/s collides with but dosent stick to the first ball. After the collision, the lighter ball moves forward with a speed of 2.3 m/s. How fast will the heavier ball move after the collision. Give your answer in meter per second.
moving speeds of v₁ = 5.2 m/s m₂ = 2m₁. After the collision Two Particles are and V₂0 and mass mi Of 90° relative to its direction prior to elastic. The collision is is observed to be moving at an angle the Collision, Define a Suitable coordinate system and determine the final velocities (including direction) of each Partille, It also may be useful to remember that cos(20) = Cos²-sin².