A 1.00-L solution contains 2.50x104 M Cu(NO3)2 and 2.00x10-3 M ethylenediamine (en). The K for Cu(en)22+ is 1.00 x 1020 Cu2+ (aq) +2en(aq) = Cu(en)2 (aq) Ke- [Cu(en)2] [Cu²+ ][en]²
A 1.00-L solution contains 2.50x104 M Cu(NO3)2 and 2.00x10-3 M ethylenediamine (en). The K for Cu(en)22+ is 1.00 x 1020 Cu2+ (aq) +2en(aq) = Cu(en)2 (aq) Ke- [Cu(en)2] [Cu²+ ][en]²
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A 1.00-L solution contains 2.50x 10-4 M Cu(NO3)2 and 2.00×10-3 M ethylenediamine (en). The Ky for Cu(en) 22+ is 1.00 × 1020
Cu²+ (aq) +2en(aq)
Cu(en)2+ (aq)
[Cu(en)2+]
K₁ [Cu²+ ][en]²
1st attempt
Feedback
1
What is the concentration of Cu2+ (aq) in the solution?
x 10 19
78125
M
tl See Perio-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9077c120-5b3f-4825-86ae-193451a028c6%2F3dcada7a-65f6-4f68-81c3-52fc6bb0202c%2F1kmj4ls_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 1.00-L solution contains 2.50x 10-4 M Cu(NO3)2 and 2.00×10-3 M ethylenediamine (en). The Ky for Cu(en) 22+ is 1.00 × 1020
Cu²+ (aq) +2en(aq)
Cu(en)2+ (aq)
[Cu(en)2+]
K₁ [Cu²+ ][en]²
1st attempt
Feedback
1
What is the concentration of Cu2+ (aq) in the solution?
x 10 19
78125
M
tl See Perio-
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