A 1.00 kg mass is attached to a massless spring. After a mass, M, is attached to the spring and it reaches equilibrium, the spring is stretched 12.0 from its free length. From this position, the mass is pulled down an additional 20.0 cm, and released. Assume no loss due to friction. The force constant of the spring is
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- An ideal spring hangs from the ceiling. A 1.65 kg1.65 kg mass is hung from the spring, stretching the spring a distance ?=0.0925 md=0.0925 m from its original length when it reaches equilibrium. The mass is then lifted up a distance ?=0.0315 mL=0.0315 m from the equilibrium position and released. What is the kinetic energy of the mass at the instant it passes back through the equilibrium position?A 0.90 kg mass is attached to a light spring with a force constant of 250.9 N/m and set into oscillation on a horizontal frictionless surface. If the spring is stretched 5.0 cm and released from rest, determine the speed of the oscillating mass (in m/s) when the spring is compressed 2.5 cm.A 5.0 kg weight is hanging from an ideal spring with a k of 250N/m. It is pulled .15m from equalibrium. Find it's maximum displacement the elastic potential energy of spring just as the block is being released the maximum speed the block will have during its motion the displacement of the block from equilibrium when the kinetic energy of the block is equal to the elastic potential energy of the spring The block is then brought to rest at equilibrium. The block is then pulled down half the original distance. Will the new period for the motion of the block be greater than, less than, or equal to the original period for the motion of the block? Why? The first block is brought to rest at equilibrium again. An identical block is launched up into the first block. The new block is moving with an initial speed of v=5.0m/s when it collides with and sticks to the original block. Calculate the maximum compression of the spring after the collision of the two blocks.
- When a 0.34-kg block is suspended on a vertical spring, it causes it to stretch 2.90 cm. If the block is now pulled 7.60cm below its equilibrium position and released, what is the speed of the block when it is 1.40 cm above the equilibriumposition?A 0.505-kg block slides on a frictionless horizontal surface with a speed of 1.18 m>s. The block encounters an unstretched spring and compresses it 23.2 cm before coming to rest. (a)What is the force constant of this spring? (b) For what length of timeis the block in contact with the spring before it comes to rest? (c) Ifthe force constant of the spring is increased, does the time required tostop the block increase, decrease, or stay the same? Explain.An ideal spring hangs from the ceiling. A 1.75 kg mass is hung from the spring, stretching the spring a distance d=0.0865 m from its original length when it reaches equilibrium. The mass is then lifted up a distance L=0.0295 m from the equilibrium position and released. What is the kinetic energy of the mass at the instant it passes back through the equilibrium position?
- A spring is hung from a ceiling, and an object attached to its lower end stretches the spring by a distance of 5.00 cm from its unstretched position when the system is in equilibrium. If the spring constant is 47.4 N/m, determine the mass of the object. kgA 1.1 kg object is suspended from a vertical sprinkler spring cost and is 190 N/m. (A)find the amount by which the spring is stretched from its unstrained length. ( B)the object is in pulled straight down by an additional distance of 0.19 m and released from rest. Find the speed with which the object passes through its original position on the way up.An automobile having a mass of 1000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with constant 4.75 106 N/m and is compressed 2.70 cm as the car is brought to rest. What was the speed of the car before impact, assuming no energy is lost in the collision with the wall? m/s
- An ideal spring hangs from the ceiling. A 1.25 kg mass is hung from the spring, stretching the spring a distance d = 0.0865 m from its original length when it reaches equilibrium. The mass is then lifted up a distance L = 0.0325 m from the equilibrium position and released. What is the kinetic energy K of the mass at the instant it passes back through the equilibrium position? K = d Equilibrium position wwwwww. wwwA 1.00-kg mass is attached to a spring hanging vertically and hangs at rest in the equilibrium position. The spring constant of the spring is 1.00 N/cm. The mass is pulled downward 2.00 cm and released. What is the speed of the mass when it is 1.00 cm above the point from which it was released? 0.0443 m/s 1.73 m/s 1.67 m/s 0.0201 m/s The mass will not reach the height specified.In the figure below a 1.24-kg block is held at rest against a spring with a force constant K = 700 N/m. Equibrum pasition Rou gh pctch X |Initially, the spring is compressed a distance d. When the block is released it slides across a surface that is frictionless, except for a rough patch of width = 4.89 cm that has a coefficient of kinetic friction k= 0.554. Calculate d such that the block's speed after crossing the rough patch is 2.44 m/s.