A 1-D harmonic oscillator is in the state ep(x) = 1/14 [3¼o(x) – 2p1(x) + µ2(x)] are the ground, first excited and second excited states, respectively. The probability of finding the oscillator in the ground state is O 9/14 O 3/V14
A 1-D harmonic oscillator is in the state ep(x) = 1/14 [3¼o(x) – 2p1(x) + µ2(x)] are the ground, first excited and second excited states, respectively. The probability of finding the oscillator in the ground state is O 9/14 O 3/V14
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![A 1-D harmonic oscillator is in the state e(x) = 1//14 [34o(x) - 241(x) + µ2(x)] are the ground, first
excited and second excited states, respectively. The probability of finding the oscillator in the ground
state is
1
9/14
3//14](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3edbcdf2-70e9-4b3e-b0fb-5dfcb2816f61%2F89ff7c67-4bfc-400d-99d1-e99bf0898b2a%2F39fg6db_processed.png&w=3840&q=75)
Transcribed Image Text:A 1-D harmonic oscillator is in the state e(x) = 1//14 [34o(x) - 241(x) + µ2(x)] are the ground, first
excited and second excited states, respectively. The probability of finding the oscillator in the ground
state is
1
9/14
3//14
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