A 0.7500-g sample of impure iron ore was treated and passed through a Jones reductor. The Fe (II) produced required 39.50 mL of 0.02000 M KMnO a. Write the balance redox reaction involved in the analysis. Write the balanced half reactions. b. Calculate the percent Fe in the ore sample. [Use the balanced redox reaction for your stoichiometric values and the titration values to find the amount of Fe. Solve for percent Fel
A 0.7500-g sample of impure iron ore was treated and passed through a Jones reductor. The Fe (II) produced required 39.50 mL of 0.02000 M KMnO a. Write the balance redox reaction involved in the analysis. Write the balanced half reactions. b. Calculate the percent Fe in the ore sample. [Use the balanced redox reaction for your stoichiometric values and the titration values to find the amount of Fe. Solve for percent Fel
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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[ 3rd ] Instructions: Kindly provide the complete and correct solutions. (There are some questions that needs to be based in a periodic table, kindly base it on the one I provided below) I won't like it if it is incomplete and incorrect.
![A 0.7500-g sample of impure iron ore was treated and passed through a
Jones reductor. The Fe (II) produced required 39.50 mL of 0.02000 M KMnO
a. Write the balance redox reaction involved in the analysis. Write the
balanced half reactions.
b. Calculate the percent Fe in the ore sample.
[Use the balanced redox reaction for your stoichiometric values and
the titration values to find the amount of Fe. Solve for percent Fe]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa830c92e-f378-44ec-b9bd-b1903d98b9c5%2F48033e48-0a93-4f7a-9586-f7e4ca2b317d%2Fqug9mqh_processed.png&w=3840&q=75)
Transcribed Image Text:A 0.7500-g sample of impure iron ore was treated and passed through a
Jones reductor. The Fe (II) produced required 39.50 mL of 0.02000 M KMnO
a. Write the balance redox reaction involved in the analysis. Write the
balanced half reactions.
b. Calculate the percent Fe in the ore sample.
[Use the balanced redox reaction for your stoichiometric values and
the titration values to find the amount of Fe. Solve for percent Fe]
Transcribed Image Text:PERIODIC TABLE OF THE ELEMENTS
IA
1
H
HA
BA
NA
VIA
16
VIIA
17
1.01
2
VA
15
7
13
14
3
5
6
8
LI
Be
с
12.01
9.01
6.94
11
N
14.01
15
B
1081
13
Al Si
26.98 28.09
O
16.00
16
F
19.00
17
12
HIB
IVB
VB
V16
VIIB
V48
n
18
118
Na
22.99
19
Mg
24.31
3
4
5
6
7
8
9
10
11
12
20
21
22
23
24
25
26
20
29
Ca
Sc
Ti
V
Mn
Fe
55.85
40.08
30
Cu Zn
63.55 65.39
47
44.96
47.87
K
39.10
37
Rb
85.47
50.94
54.94
CI
35.45
35
Br
79.90
53
1
27
Co
58.93
45
Rh
Pd
Ag
Cd
102.91 106.42 107.87 112.41
Ni
58.69
46
30.97 32.07
31
34
Ga Ge
Se
69.72 72.64
78.96
49
50
52
In Sn Sb Te
11482 118.71 121.76 127.60 126.90
As
74.92
51
38
Cr
52.00
42
Mo
95.94
74
39
40
48
Sr
Y
88.91
Zr
91.22
87.62
56
Nb
92.91
73
Tc
(98)
75
71
72
79
80
81
85
55
Cs
Ba Lu
132.91 137.33 173.04
Hf
Ta
W
Re
Ru
101.07
76
77
76
Os Ir Pt
190.23 192.22 195.08
108
109
110
Hs
Mt Ds
(269) (278) (281)
82
Au Hg TI Pb
196.97 200.59 204.38 207.20
111
112
113
114
83
Bi
208.98
115
178.49
180.95
183.84 186.21
84
Po
(209)
116
LV Uus
(293) (294)
At
(210)
117
103
104
105
106
107
87
88
Fr Ra
Lr
Rf
Sg Bh
Db
(268)
Uup
Rg Cn
(280)
Uut FI
(286) (289)
(223) (226) (262)
(267)
(269)
(270)
(285)
(288)
57
58
59
60
61
62
66
Ce
Lanthanide
Series
La
138.91 140.12
Pr Nd
140.91 144.24
Pm
(145)
93
63
Sm Eu
150.36 151.96
67
68
69
Dy Ho Er Tm
162.50 164.93 167.26 168.93
70
Yb
173.04
64
65
Gd Tb
157.25 158.93
96
97
98
Cm Bk Cf
(247) (247) (251) (252)
90
92
100
101
102
89
91
Ac Th Pa
(227) 232.04 231.04 238.03
Actinide
95
Np Pu
Am
(237) (244) (243)
99
Es
Fm
Md
No
Senes
(257)
(258)
(259)
C
F
18
2
He
4.00
10
Ne
20.18
18
Ar
39.95
36
Kr
83.80
54
Xe
131.29
96
Rn
(222)
118
Uuo
(294)
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