A 0.658 g sample of a diprotic acid is dissolved in water and titrated with 0.130 M NaOH. What is the molar mass of the acid if 38.4 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. molar mass: g/mol

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Chapter1: Chemical Foundations
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A 0.658 g sample of a diprotic acid is dissolved in water and
titrated with 0.130 M NAOH. What is the molar mass of the
acid if 38.4 mL of the NaOH solution is required to neutralize
the sample? Assume the volume of NaOH corresponds to the
second equivalence point.
10
11
12
13
molar mass:
g/mol
18
19
20
21
22
23
24
Transcribed Image Text:A 0.658 g sample of a diprotic acid is dissolved in water and titrated with 0.130 M NAOH. What is the molar mass of the acid if 38.4 mL of the NaOH solution is required to neutralize the sample? Assume the volume of NaOH corresponds to the second equivalence point. 10 11 12 13 molar mass: g/mol 18 19 20 21 22 23 24
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