A 0.620 kg PYREX® glass calorimeter contains 0.400 kg of water at 12.8°C (both in thermal equilibrium). At that time, 1,000 kg of solid mercury is added at a temperature of -39°C, which corresponds to the melting point of mercury. a) Describe which parts of the system will give up thermal energy and which will gain thermal energy. Discuss which elements require less energy for phase changes or temperature changes.

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A 0.620 kg PYREX® glass calorimeter contains 0.400 kg of water at 12.8°C (both in thermal
equilibrium). At that time, 1,000 kg of solid mercury is added at a temperature of -39°C,
which corresponds to the melting point of mercury.
a) Describe which parts of the system will give up thermal energy and which will gain thermal
energy. Discuss which elements require less energy for phase changes or temperature
changes.
b) Find the equilibrium temperature.
c) Describe the states of water and mercury once thermal equilibrium is reached.
J
CPYREXⓇ
= 703
.. K; CHg
kg
= 1,18 x 104
=
138
. K; CH₂0
kg
= 4190
-; LƒH₂0 = 3,34 x 105
kg
J
kg
c is specific heat
Lf is latent heat of fusion
=
. K; Cice
2100 K; LƒHg
kg
Transcribed Image Text:A 0.620 kg PYREX® glass calorimeter contains 0.400 kg of water at 12.8°C (both in thermal equilibrium). At that time, 1,000 kg of solid mercury is added at a temperature of -39°C, which corresponds to the melting point of mercury. a) Describe which parts of the system will give up thermal energy and which will gain thermal energy. Discuss which elements require less energy for phase changes or temperature changes. b) Find the equilibrium temperature. c) Describe the states of water and mercury once thermal equilibrium is reached. J CPYREXⓇ = 703 .. K; CHg kg = 1,18 x 104 = 138 . K; CH₂0 kg = 4190 -; LƒH₂0 = 3,34 x 105 kg J kg c is specific heat Lf is latent heat of fusion = . K; Cice 2100 K; LƒHg kg
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