A 0.5657-g sample of a chlorocarbon compound was analyzed for its chloride content by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After neutralizing, the sample was treated with 42.25 mL of a 0.2320 M AgNO3 solution. This precipitated the chloride (CI") out as AgCl and left an excess of AgNO3. The excess AgNO3 was titrated with 0.1326 M KSCN and required 18.47 mL to reach equivalence. Calculate the % w/w CI- (35.45 g/mol) in the sample. Provide your answer to two places after the decimal point and without units. Reactions: A9CI (s) Ag+ + SCN- → A9SCN (s) Ag+ + Cl
A 0.5657-g sample of a chlorocarbon compound was analyzed for its chloride content by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After neutralizing, the sample was treated with 42.25 mL of a 0.2320 M AgNO3 solution. This precipitated the chloride (CI") out as AgCl and left an excess of AgNO3. The excess AgNO3 was titrated with 0.1326 M KSCN and required 18.47 mL to reach equivalence. Calculate the % w/w CI- (35.45 g/mol) in the sample. Provide your answer to two places after the decimal point and without units. Reactions: A9CI (s) Ag+ + SCN- → A9SCN (s) Ag+ + Cl
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A 0.5657-g sample of a chlorocarbon compound was analyzed for its chloride content by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After
neutralizing, the sample was treated with 42.25 mL of a 0.2320 M AgNO3 solution. This precipitated the chloride (CI") out as AgCl and left an excess of AgNO3. The excess
AGNO3 was titrated with 0.1326 M KSCN and required 18.47 mL to reach equivalence.
Calculate the % w/w CI (35.45 g/mol) in the sample. Provide your answer to two places after the decimal point and without units.
Reactions:
→ AgCl (s)
→ AGSCN (s)
Ag+ + Cl-
Ag+ + SCN-
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