A 0.540 gg sample of a diprotic acid with a molar mass of 255.8 g/molg/mol is dissolved in water to a total volume of 30.0 mLmL . The solution is then titrated with a saturated calcium hydroxide solution (Ksp(Ca(OH)2)=4.68×10−6) a. Assuming that the pKapKa values for each ionization step are sufficiently different to see two equivalence points, determine the volume of added base for the first and second equivalence points. b. The pH after adding 30.0 mLmL of the base was 3.60. Find the value of pKa1 c. The pH after adding 28.0 mLmL past the first equivalence point was 8.15. Find the value of pKa2.
A 0.540 gg sample of a diprotic acid with a molar mass of 255.8 g/molg/mol is dissolved in water to a total volume of 30.0 mLmL . The solution is then titrated with a saturated calcium hydroxide solution (Ksp(Ca(OH)2)=4.68×10−6) a. Assuming that the pKapKa values for each ionization step are sufficiently different to see two equivalence points, determine the volume of added base for the first and second equivalence points. b. The pH after adding 30.0 mLmL of the base was 3.60. Find the value of pKa1 c. The pH after adding 28.0 mLmL past the first equivalence point was 8.15. Find the value of pKa2.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 0.540 gg sample of a diprotic acid with a molar mass of 255.8 g/molg/mol is dissolved in water to a total volume of 30.0 mLmL . The solution is then titrated with a saturated calcium hydroxide solution (Ksp(Ca(OH)2)=4.68×10−6)
a. Assuming that the pKapKa values for each ionization step are sufficiently different to see two equivalence points, determine the volume of added base for the first and second equivalence points.
b. The pH after adding 30.0 mLmL of the base was 3.60. Find the value of pKa1
c. The pH after adding 28.0 mLmL past the first equivalence point was 8.15. Find the value of pKa2.
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