A 0.5-kg object initially resting on a horizontal (frictionless) air track at x = 1 m is subject to two forces: F₁ is a constant force of magnitude 20 N directed vertically downward, while F2 acts along the x-axis and varies as shown in the figure below. The speed (in m/s) of the object after it undergoes a displacement of 5 m along the positive x-direction is: ↑10 F(N) 5 0 -5 -10 LAF 3 45 6 10.0 8.9 107.7 108.9 7.7 The correct answer is: 7,7
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- An airliner of mass 1.70 * 105 kg lands at a speed of 75.0 m>s. As it travels along the runway, the combined effects of air resistance, friction from the tires, and reverse thrust from the engines produce a constant force of 2.90 * 105 N opposite to the airliner’s motion. What distance along the runway does the airliner travel before coming to a halt?A parachutist whose mass is 85 kg drops from a helicopter hovering 2000 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b 1 = 20 N - sec/m when the chute is closed and b 2 = 90 N - sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 35 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/ sec ^2The force acting on a particle is F - (10x – 17) N, where x is in meters. (a) Make a plot of this force versus x from x = 0 to x = 3.00 m. F (N) F (N) 20 50 40 10- 30 0,5 20 1.0 20 25 x (m) 30 -10 10 atx (m) 3.0 0.5 1.0 1.5 2.0 2.5 F (N) F (N) 0,5 1.0 1,5 2.0 2.5 x (m) 30 10 -10 -20 0,5 15 x (m) 30 10 2.5 -30 -10 -40 -50 -20 (b) From your graph, find the net work done by this force on the particle as it moves from x = 0 to x= 2.55 m. (Include the correct sign.)
- A 70-pound object is thrown upward with an initial velocity of 45 ft/s along a plane inclined 25 ° from the horizontal, as shown in Figure. The coefficient of friction between the plane and the object is 0.15. Determine: a) The maximum distance that it will climb on the inclined plane. b) The speed of the object when it returns to the starting point. p/s = ft/sA parachutist whose mass is 65 kg drops from a helicopter hovering 1500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b₁ = 20 N-sec/m when the chute is closed and b₂ = 90 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 25 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec². The parachutist will reach the ground after (Round to two decimal places as needed.) seconds.A parachutist whose mass is 80 kg drops from a helicopter hovering 1500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b₁ = 20 N-sec/m when the chute is closed and b₂ = 100 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 30 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec². The parachutist will reach the ground after (Round to two decimal places as needed.) seconds. (・・・)
- Consider an object sliding down a frictionless ramp that is inclined an angle above 0 the horizontal. Which equation best represents the object's actual acceleration perpendicular to the ramp ay? Think carefully: What does the object actually do in the y-direction? mg PM (99+) $ 4 R F % V S 5 T G C 6 B ◄ Y & 7 8 U H J N M ( C K O O L Ö ? 80°F inserA parachutist whose mass is 80 kg drops from a helicopter hovering 1000 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b, = 30 N-sec/m when the chute is closed and b, = 90 N-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 20 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/ sec.A parachutist whose mass is 65 kg drops from a helicopter hovering 2500 m above the ground and falls toward the ground under the influence of gravity. Assume that the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b_1 = 20 N*sec/m when the chute is closed and b_2 = 90 N*sec/m when the chute is open. If the chute does not open until the velocity of the parachutist reaches 25 m/sec, after how many seconds will the parachutist reach the ground? Assume that the acceleration due to gravity is 9.81 m/sec^2. How much time will the parachutist reach the ground after? (Round up your answer to two decimal places as needed.)
- A brick of mass 1.00 kg slides down an icy roof inclined at 30.0° with respect to the horizontal. If the brick starts from rest, how fast is it moving when it reaches the edge of the roof 2.18 m away? Ignore friction. m/s"A 10.0 kg block initially at rest is pulled to the right along a horizontal, frictionless surface by a constant horizontal force of 36 N. Find the speed of the block after it has moved 2.0 m." 3.8 m/s 7.2 m/s v = 0 The data is not enough to calculate the speedA skateboarder with mass m, = 44 kg is standing at the top of a ramp which is h, = 3.9 m above the ground. The skateboarder then jumps on his skateboard and descends down the ramp. His speed at the bottom of the ramp is v= 6.7 m/s. Part (b) The ramp makes an angle e with the ground, where 0 = 30°. Write an expression for the magnitude of the friction force, f, between the ramp and the skateboarder. cos(e) sin(e) 8 HOME a 5 6 1 2 3 h, P . END m, + Vf vol BACKSPACE CLEAR Part (c) When the skateboarder reaches the bottom of the ramp, he continues moving with the speed vfonto a flat surface covered with grass. The friction between the grass and the skateboarder brings him to a complete stop after 5.00 m. Calculate the magnitude of the friction force, Fgras; in newtons, between the skateboarder and the grass. Fgrazs =