A 0.5 Hp 2-pole single-phase motor is operated in 240 V 50 Hz network. The motor operates with 3.4% slip at full load. In the locked rotor test, the following measurements were taken from the main winding and auxiliary windings. Auxiliary Winding Main Winding Applied Voltage E=24V E=24V Current Is=5 A Ia=2A Active power Ps=75W Pa=30W a- Calculate the rotor speed (nr) b- Calculate the phase difference between the main winding and the auxiliary winding. c- Calculate the power it will draw from the mains if the rotor is locked at 240 Volt mains voltage.

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A 0.5 Hp 2-pole single-phase motor is operated in 240 v 50 Hz network. The motor operates
with 3.4% slip at full load. In the locked rotor test, the following measurements were taken
from the main winding and auxiliary windings.
Auxiliary
Winding
Main
Winding
Applied Voltage
E=24V
E=24V
Current
Is=5 A
Ia=2A
Active power
Ps=75W
Pa=30W
a- Calculate the rotor speed (nr)
b- Calculate the phase difference between the main winding and the auxiliary winding.
c- Calculate the power it will draw from the mains if the rotor is locked at 240 Volt
mains voltage.
Transcribed Image Text:A 0.5 Hp 2-pole single-phase motor is operated in 240 v 50 Hz network. The motor operates with 3.4% slip at full load. In the locked rotor test, the following measurements were taken from the main winding and auxiliary windings. Auxiliary Winding Main Winding Applied Voltage E=24V E=24V Current Is=5 A Ia=2A Active power Ps=75W Pa=30W a- Calculate the rotor speed (nr) b- Calculate the phase difference between the main winding and the auxiliary winding. c- Calculate the power it will draw from the mains if the rotor is locked at 240 Volt mains voltage.
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