A 0.465 g sample of an unknown compound occupies 245 mL at 298 K and 1.22 atm. What is the molar mass of the unknown compound?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem Statement:**

A 0.465 g sample of an unknown compound occupies 245 mL at 298 K and 1.22 atm. What is the molar mass of the unknown compound?

**Answer Choices:**

1. 38.0 g/mol
2. 26.3 g/mol
3. 26.3 g/mol
4. 81.8 g/mol
5. 33.9 g/mol

**Explanation:**

To determine the molar mass of the unknown compound, you will need to use the Ideal Gas Law, which is given by the equation:

\[ PV = nRT \]

Where:
- \(P\) is the pressure in atmospheres (atm)
- \(V\) is the volume in liters (L)
- \(n\) is the number of moles (mol)
- \(R\) is the ideal gas constant \((0.0821 \, \text{L atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1})\)
- \(T\) is the temperature in Kelvin (K)

1. **Convert the volume from milliliters to liters:**
   \[
   V = 245 \, \text{mL} \times \frac{1 \, \text{L}}{1000 \, \text{mL}} = 0.245 \, \text{L}
   \]

2. **Rearrange the Ideal Gas Law to solve for \(n\):**
   \[
   n = \frac{PV}{RT}
   \]
   Substituting the known values:
   \[
   n = \frac{(1.22 \, \text{atm}) \times (0.245 \, \text{L})}{(0.0821 \, \text{L atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}) \times (298 \, \text{K})}
   \]
   \[
   n \approx 0.0122 \, \text{mol}
   \]

3. **Determine the molar mass (M) using the mass (m) and the number of moles (n):**
   \[
   M = \frac{m}{n}
   \]
   Given the mass
Transcribed Image Text:**Problem Statement:** A 0.465 g sample of an unknown compound occupies 245 mL at 298 K and 1.22 atm. What is the molar mass of the unknown compound? **Answer Choices:** 1. 38.0 g/mol 2. 26.3 g/mol 3. 26.3 g/mol 4. 81.8 g/mol 5. 33.9 g/mol **Explanation:** To determine the molar mass of the unknown compound, you will need to use the Ideal Gas Law, which is given by the equation: \[ PV = nRT \] Where: - \(P\) is the pressure in atmospheres (atm) - \(V\) is the volume in liters (L) - \(n\) is the number of moles (mol) - \(R\) is the ideal gas constant \((0.0821 \, \text{L atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1})\) - \(T\) is the temperature in Kelvin (K) 1. **Convert the volume from milliliters to liters:** \[ V = 245 \, \text{mL} \times \frac{1 \, \text{L}}{1000 \, \text{mL}} = 0.245 \, \text{L} \] 2. **Rearrange the Ideal Gas Law to solve for \(n\):** \[ n = \frac{PV}{RT} \] Substituting the known values: \[ n = \frac{(1.22 \, \text{atm}) \times (0.245 \, \text{L})}{(0.0821 \, \text{L atm} \cdot \text{K}^{-1} \cdot \text{mol}^{-1}) \times (298 \, \text{K})} \] \[ n \approx 0.0122 \, \text{mol} \] 3. **Determine the molar mass (M) using the mass (m) and the number of moles (n):** \[ M = \frac{m}{n} \] Given the mass
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