A 0.4366 g sample of a compound of carbon, oxygen and hydrogen is burned completely and 453 mL of CO2 is formed at 745 torr and 0 C. In another experiment, a 0.3651 g sample of the compound was found to contain 33.5 mg of hydrogen. In a final experiment a gaseous sample had a density of 0.579 g/L at 302 Č and 236 mmHg. Find the molecular formula of the compound

A 0.4366 g sample of a compound of carbon, oxygen and hydrogen is burned completely and 453 mL of CO2 is formed at 745 torr and 0 C. In another experiment, a 0.3651 g sample of the compound was found to contain 33.5 mg of hydrogen. In a final experiment a gaseous sample had a density of 0.579 g/L at 302 Č and 236 mmHg. Find the molecular formula of the compound

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

Question

A 0.4366 g sample of a compound of carbon,
oxygen and hydrogen is burned completely and
453 mL of CO2 is formed at 745 torr and 0 C. In
another experiment, a 0.3651g sample of the
compound was found to contain 33.5 mg of
hydrogen. In a final experiment a gaseous sample
had a density of 0.579 g/L at 302 Č and 236
mmHg. Find the molecular formula of the
compound

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