A 0.4 kg mass, attached to the end of a 0.75 m string, is whirled around in a circular vertical path. The maximum tension that the string can withstand is 20 N. A. What minimum speed would the mass be moving if the string broke at the top of the circle? B. What minimum speed would cause the string to break at the bottom of the circle? C. Now let the mass be half way between the top and bottom of the vertical circle (at 9 o'clock on a clock face). If the speed is just at the breaking strength of the string, what is the magnitude and direction of the mass' acceleration?

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Directions: Use g = 9.80 m/s2 and assume all numbers are accurate to 3 significant
figures unless otherwise indicated.

A 0.4 kg mass, attached to the end of a 0.75 m string, is whirled around in a circular vertical path. The maximum tension that the string can withstand is 20 N. 

A. What minimum speed would the mass be moving if the string broke at the top of the circle?

B. What minimum speed would cause the string to break at the bottom of the circle?

C. Now let the mass be halfway between the top and bottom of the vertical circle (at 9 o’clock on a clock face). If the speed is just at the breaking strength of the string, what is the magnitude and direction of the mass’ acceleration?
Transcribed Image Text:A 0.4 kg mass, attached to the end of a 0.75 m string, is whirled around in a circular vertical path. The maximum tension that the string can withstand is 20 N. A. What minimum speed would the mass be moving if the string broke at the top of the circle? B. What minimum speed would cause the string to break at the bottom of the circle? C. Now let the mass be halfway between the top and bottom of the vertical circle (at 9 o’clock on a clock face). If the speed is just at the breaking strength of the string, what is the magnitude and direction of the mass’ acceleration?
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