#1 1. A 0.35 kg ball is being whirled around at constant speed in a conical pendulum at the end of a 1.0 m string. Explain why the tension in the string does zero work on the ball.**Diagram Explanation:**The diagram illustrates a conical pendulum setup. A ball is attached to a string, creating an angle as it moves in a horizontal circular path. The string is connected to a fixed point above, forming a conical shape as the ball moves. The path of the ball is a circle, depicted by a purple dotted line, indicating the motion in a horizontal plane. The force of tension acts along the string, towards the pivot point, illustrating the direction of the force applied. The center of this circle aligns with the vertical line representing the gravitational force acting downward. **Concept Explanation:**The tension in the string does zero work on the ball because work is defined as the force applied in the direction of the displacement. Here, the tension force is always perpendicular to the velocity of the ball since it moves in a circular path. Because these forces are perpendicular, no work is done by the tension on the moving ball.

Answered: Image /qna-images/answer/a598712e-c295-4f2c-9ae8-e175638016d6.jpg

Answered: A 0.35 kg ball is being whirled around…

A 0.35 kg ball is being whirled around at constant speed in a conical pendulum at the end 1. of a 1.0 m string. Explain why the tension in the string does zero work on the ball.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A 1000 kg car traveling at 30 m/s crashes into a wall and come to rest in a distance of 2.5 m.…

A: Given that mass of the car and initial velocity of the car and also given the final velocity of the…

Q: Q2 (a) Based on the straight current-carrying filamentary conductor of length AB as can be viewed in…

A: (a) Given: OA=OB=1m, I=8A Refer to the figure below :

Q: A hot air balloon has just lifted off and is rising at a constant rate of 2.0 m/s. Suddenly one of…

Q: READING: T1 (C) |T2 ('C) 20 V(mv) 41 60 20 9.9 80 20 14.9 100 20 20 RUSULTS: 1. Draw the…

A: Let ΔT denotes the temperature difference and V denotes the voltage to the corresponding temperature…

Q: Given A = 21+}-3k andB = -i+2}. The magnitude of 38-A is %3D Select one: a. 7.68 b. 9.28 O c. 8.96 O…

A: Option A is the right answer 7.68

Q: 4) Two vectors, A= 2x 3y and B= 4x 4y. The magnitude of A+B is: A) 4.3 B) 5.1 C) 7.8 D) 6.4 E) 9.2

A: A→=2x^-3y^B→=4x^-4y^where x^ and y^ are unit vectors along x and y directionso…

Q: tubular cross- section toroid An ideal toroid with inner radius b and outer radius and carrying a…

A: Given, Magnitude of magnetic field B=μ0NI2πr and area segment dA=2πrdr

Q: Q10) What is the angle between the two vectors A= 5i+ 6j and B = 31- 3/? A) 109° B) 95 C) 120° D)…

A: Given data The vector A is given as A→=5i^+6j^. The vector B is given as B→=3i^-3j^.

Q: This time you put a nucleus with 8 protons on the x-axis at x = 3.0 Angstroms. There will be a place…

A: Given that: Q=+8e at x=3 Angstroms

Q: how did it become 6.92?

A: Given that, the resistance of the resistors are R4=1kΩ=1000ΩR5=2kΩ=2000Ω the voltage drop across R4…

Q: 14.3 N 11.7 N 24.7 N 30.5 N F1 12.3 N F2 3.4 N

Q: 2,3,1

Q: 3

A: Given as,

Q: [A,x] = -ih m -Px

Q: In the higure. the long straight wire carries a current of 30 A and the rectangular loop carries a…

A: Scenario - A loop and a wire are placed in Y-Z plane such that loop is a little far from the wire.…

Q: Determine the resultant for the forces showing in figure (15) . at paint (0). Q 16 F Fig. (16)

Q: B) Let u = 5i-j+k, v = j-5k, w = -15i+3j-3k. Which vectors if any, are 1) perpendicular? 2)…

Q: 7. IS this scenario possible?

A: In this question it is asked that if acceleration vector is not constant then magnitude of…

Q: The angle made by the two vectors S=3 i +4j+5k and M=3i+4j+5k is: A) 90 B 45 C) 0 D) 180 E) No…

A: Given:- Two vectors are as S→ = 3i^+4j^+5k^M→= 3i^+4j^+5k^ Find:- The angle made by the two…

Q: Now you have a nucleus with 19 protons at x = 6.3 Angstroms on the x-axis. How much work would it…

Q: > Find force 0 = 40° d = 10 mm- V = 35 m/s U = 15 m/s D = 20 m

Q: can you do the third question

Q: A person walks first at a constant speed of 5m/s along a straight line from point A to point B and…

A: Let 'd' be the distance between point A and point B. Constant speed to person from A to B: v1 = 5…

Q: A cannonball is launched diagonally with an initial horizontal velocity of 38.0m/s. Label the…

A: (1) Given: The initial horizontal velocity is 38.0 m/s. The angle of launch is 23.0°.

Q: 3] The angle between the vector r = 2i- j- 3k and the positive z-axis is:

Q: Ok now solve 4 and 5.

A: x(t)=(0.045)cos270t + 0.8m=5.5 kg

Q: B = 107 t Yo = 720s 3.5 km Y= Yo⋅ exp(B.t) Show how the above formula ic Calculate belo- oys used.

Q: 3. Refer back to Figure 8.1. For which types of electromagnetic radiation is the atmosphere of the…

A: Required : For which type of electromagnetic radiation, is the atmosphere of the Earth completely…

Q: ) Define the det product ICl=C_ two vecters Ã and B, which ane glven as AAx T+ A+ AzE and B Bx+ By…

Q: 8. Let a = i + 2j − k, b = −i + j + k, and c = i + k. Which vectors, if any, are (a) perpendicular?…

A: As we know that, (1) If the dot product of the vectors is zero, a.b = 0 Then both vectors are…

Q: CO 9. A boat moves from a point A(6-5)to another point acress the river. The new position of the…

A: Given : rA = 4i + 5j rB = -7i - 9j

Q: Consider again the situation given in Problem 1. (a) Find the center-of-mass of the system made up…

A: as there were no numerical values , I have left the answers in given variables.

Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

1. A 0.35 kg ball is being whirled around at constant speed in a conical pendulum at the end of a 1.0 m string. Explain why the tension in the string does zero work on the ball.

**Diagram Explanation:**
The diagram illustrates a conical pendulum setup. A ball is attached to a string, creating an angle as it moves in a horizontal circular path. The string is connected to a fixed point above, forming a conical shape as the ball moves. The path of the ball is a circle, depicted by a purple dotted line, indicating the motion in a horizontal plane. The force of tension acts along the string, towards the pivot point, illustrating the direction of the force applied. The center of this circle aligns with the vertical line representing the gravitational force acting downward.

**Concept Explanation:**
The tension in the string does zero work on the ball because work is defined as the force applied in the direction of the displacement. Here, the tension force is always perpendicular to the velocity of the ball since it moves in a circular path. Because these forces are perpendicular, no work is done by the tension on the moving ball.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

40) A = 3î + 2î ve B = -î – 4ĵ ' Calculate the angle between the vectors. A) 82,4 derece B) 43,6 derece C) 76,3 derece D) 60,2 derece E) 28,4 derece
ANY HELP WOULD BE APPRECIATED, THANKS
A baggage handler at an airport applies a constant horizontal force with magnitude F₁ to push a box, of mass M, across a rough horizontal surface with a very small constant acceleration a. ( Figure 1) Figure 2F Submit ▾ Part B Now assume that the baggage handler pushes a third box (Figure 2) of mass m/2 so that it accelerates at a rate of 2a. How does the magnitude of the force F that the handler applies to this box compare to the magnitude of the force F₁ applied to the first box? ▸ View Available Hint(s) 0 2F Submit
Question: Given vectors, which one is correct? A) C+5- A+E B) C-B= A- B D. B. D) C-5-A+ B E) Č+B = Ã - E
Q7) Calculate the angle between the two vectors A = i – 3j + k and B = 2i – j. A) 97.6° B) 47.6° C) -127.6° D) 127.6°
Question-1) Calculate the commutator (Jiz, J) where J J,+ J2.
(2) The box with M = 40kg shown below is being pulled by two pulleys exerting forces F₁ = 400 N (0₁ = 60°) and F₂ = 200 N (0₂= 15°) up an incline with an angle 0₁ = 30°. If the uk = 0.15. What is the acceleration of the box? Would the F₁ or F₂ be enough alone to pull the box up if the other pulley would stop working?
Determine which sets of vectors are orthogonal.
Question 4
Question #2 of the attachment. Thank you in advance
Problem 4: Speed deamplifier. In the figure above on the right, block 1 of mass m1 slides along an x-axis on a frictionless floor at speed 4 m/sec.Then it undergoes a one-dimensional elastic collision with stationary block 2 of mass m2 = 2m1. Next, block 2 undergoes a one-dimensional elastic collision with stationary block 3 of mass mz = 4m1. What then is the speed of block 3? Answer: 16 m/sec or 1.78 m/sec.