A 0.34 kg particle moves in an xy plane according to x(t) = - 15 + 1t-3t3 and y(t) = 24 +5t- 10 t2, with x and y in meters and t in seconds. At t = 1.2 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel? (a) Number Units (b) Number Units (c) Number Units
A 0.34 kg particle moves in an xy plane according to x(t) = - 15 + 1t-3t3 and y(t) = 24 +5t- 10 t2, with x and y in meters and t in seconds. At t = 1.2 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel? (a) Number Units (b) Number Units (c) Number Units
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![A 0.34 kg particle moves in an xy plane according to x(t) = - 15 + 1t-3t3 and y(t) = 24 + 5 t - 10 t2, with x and y in meters and t in
seconds. At t = 1.2 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x
axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
(a) Number
Units
(b) Number
Units
(c) Number
Units](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10115ea5-5f0e-4fb5-b400-8bf897ed7680%2F76640e26-ecd8-4327-ae7d-38673f0b3413%2Fnpq42rt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 0.34 kg particle moves in an xy plane according to x(t) = - 15 + 1t-3t3 and y(t) = 24 + 5 t - 10 t2, with x and y in meters and t in
seconds. At t = 1.2 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x
axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
(a) Number
Units
(b) Number
Units
(c) Number
Units
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