A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the vall over the course of the collision. What is the magnitude of the velocity, or final speed, of the car after the collision? final speed = m/s TOOLS 45- x10 0.01 0.02 0. Time (s) Force (N)
A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the vall over the course of the collision. What is the magnitude of the velocity, or final speed, of the car after the collision? final speed = m/s TOOLS 45- x10 0.01 0.02 0. Time (s) Force (N)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question
![**Collision Analysis of a Toy Car**
A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the wall over the course of the collision.
**Problem Statement:**
What is the magnitude of the velocity, or final speed, of the car after the collision?
**Graph Analysis:**
- **X-Axis (Time, s):** The time interval ranges from 0 to 0.02 seconds.
- **Y-Axis (Force, N):** The force exerted is measured from 0 to 45 Newtons.
- **Graph Description:** The force applied to the car increases linearly, reaches a maximum of 45 N at approximately 0.01 seconds, and then decreases linearly back to zero at 0.02 seconds. This creates a triangular shape.
**Calculation:**
To find the final speed of the car, consider using the impulse-momentum theorem, which relates the change in momentum to the impulse experienced. The area under the force-time graph will give the impulse.
\[ \text{Impulse} = \Delta p = F \cdot \Delta t \]
Calculate the area under the triangular force-time graph to determine the impulse, then use it to find the change in velocity.
**Final Speed Calculation Box:**
\[ \text{Final Speed} = \quad \text{m/s} \]
**Note:** Ensure to integrate or calculate the area of the triangle for accurate results. Use tools like calculators for numerical computations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F518a9830-87bc-492b-a0d3-d0bffb9858cc%2Ff04f64fc-f6be-4e06-afc6-d968f5436ff1%2Fzxxa1o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Collision Analysis of a Toy Car**
A 0.300 kg toy car moving with a speed of 0.820 m/s collides with a wall. The figure shows the force exerted on the car by the wall over the course of the collision.
**Problem Statement:**
What is the magnitude of the velocity, or final speed, of the car after the collision?
**Graph Analysis:**
- **X-Axis (Time, s):** The time interval ranges from 0 to 0.02 seconds.
- **Y-Axis (Force, N):** The force exerted is measured from 0 to 45 Newtons.
- **Graph Description:** The force applied to the car increases linearly, reaches a maximum of 45 N at approximately 0.01 seconds, and then decreases linearly back to zero at 0.02 seconds. This creates a triangular shape.
**Calculation:**
To find the final speed of the car, consider using the impulse-momentum theorem, which relates the change in momentum to the impulse experienced. The area under the force-time graph will give the impulse.
\[ \text{Impulse} = \Delta p = F \cdot \Delta t \]
Calculate the area under the triangular force-time graph to determine the impulse, then use it to find the change in velocity.
**Final Speed Calculation Box:**
\[ \text{Final Speed} = \quad \text{m/s} \]
**Note:** Ensure to integrate or calculate the area of the triangle for accurate results. Use tools like calculators for numerical computations.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning

University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley

College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON